PHP 超时不会停止脚本？

Question

我期待一些错误，例如 500 或带有以下代码的超时页面:

<?php
      ini_set('max_execution_time',5);
      set_time_limit(5);
      echo 'start';
      sleep(10);
      echo '<br/>hi';

但是，我得到这样的结果:

starthi

Did I do something incorrect?

All I want is see the script stoped when timesout in the 5thd second, so the second echo should not be executed(I know this is quite a weird requirement)

Could anyone shred a light, thanks.

PS: seems the sleep() part is quite a distraction, how about I change the code like this:

<?php
      ini_set('max_execution_time',5);
      set_time_limit(5);
      echo 'start';
      for($i=1;$i<100000000;$i++){
          if($i%100==2) echo $i;
          else echo '--';
      }
      echo '<br/>hi';

Answer 1

根据 php.net 中的评论，您必须使用 unix... "Please note that, under Linux, sleeping time is ignored, but under Windows, it counts as execution time." (在 Unix/Linux 中， sleep 不被视为执行时间的一部分。)

此外，要使其超时，只需永远循环

<?php
while (true) {
    // i'll error out after max_execution_time
}

要查看执行时间，您可以使用 microtime 找出执行时间或者查询刚刚设置的 max_execution_time 变量。

$max_time = ini_get("max_execution_time");
echo $max_time
?>

更新使用更新后的代码，输出符合预期。

Fatal error: Maximum execution time of 5 seconds exceeded in newfile.php on line 7