makefile - 对带有空格的文件名使用makefile通配符命令

Question

我有一个用于压缩图片的makefile：

src=$(wildcard Photos/*.jpg) $(wildcard Photos/*.JPG)
out=$(subst Photos,Compressed,$(src))

all : $(out)

clean:
    @rmdir -r Compressed

Compressed:
    @mkdir Compressed

Compressed/%.jpg: Photos/%.jpg Compressed
    @echo "Compressing $<"
    @convert "$<" -scale 20% "$@"

Compressed/%.JPG: Photos/%.JPG Compressed
    @echo "Compressing $<"
    @convert "$<" -scale 20% "$@"

但是，当我的图片名称中带有空格（例如 Piper PA-28-236 Dakota.JPG）时，出现此错误：

make: *** No rule to make target `Compressed/Piper', needed by `all'.  Stop.

我认为这是 wildcard命令中的问题，但是我不确定要对其进行更改需要进行哪些更改。

如何修改我的makefile以在文件名中保留空格？

Answer 1

通常，使用make在文件名中包含空格是一个坏主意，但对于您而言，这可能有效：

src=$(shell find Photos/ -iname '*.JPG' | sed 's/ /\\ /g')

out=$(subst Photos,Compressed,$(src))

all : $(out)

Compressed:
  @mkdir Compressed

Compressed/%: Photos/% Compressed
  @echo "Compressing $<"
  @convert "$<" -scale 20% "$@"