spring-mvc - 如何测试 DeferredResult timeoutResult

Question

我正在实现 long polling as per the Spring blog from some time ago .

这里我转换的方法与以前具有相同的响应签名，但不是立即响应，它现在使用长轮询:

private Map<String, DeferredResult<ResponseEntity<?>>> requests = new ConcurrentHashMap<>();

@RequestMapping(value = "/{uuid}", method = RequestMethod.GET)
public DeferredResult<ResponseEntity<?>> poll(@PathVariable("uuid") final String uuid) {
    // Create & store a new instance
    ResponseEntity<?> pendingOnTimeout = ResponseEntity.accepted().build();
    DeferredResult<ResponseEntity<?>> deferredResult = new DeferredResult<>(TWENTYFIVE_SECONDS, pendingOnTimeout);
    requests.put(uuid, deferredResult);

    // Clean up poll requests when done
    deferredResult.onCompletion(() -> {
        requests.remove(deferredResult);
    });

    // Set result if already available
    Task task = taskHolder.retrieve(uuid);
    if (task == null)
        deferredResult.setResult(ResponseEntity.status(HttpStatus.GONE).build());
    else
        // Done (or canceled): Redirect to retrieve file contents
        if (task.getFutureFile().isDone())
            deferredResult.setResult(ResponseEntity.created(RetrieveController.uri(uuid)).build());

    // Return result
    return deferredResult;
}

我特别想返回 pendingOnTimeout当请求时间过长时响应(我之前立即返回)，以防止代理切断请求。

现在我想我已经按原样工作了，但我想编写一个单元测试来确认这一点。然而，我使用 MockMvc(通过 webAppContextSetup)的所有尝试都未能为我提供一种断言我得到 accepted 的方法。标题。例如，当我尝试以下操作时:

@Test
public void pollPending() throws Exception {
    MvcResult result = mockMvc.perform(get("/poll/{uuid}", uuidPending)).andReturn();
    mockMvc.perform(asyncDispatch(result))
            .andExpect(status().isAccepted());
}

我得到以下堆栈跟踪:

java.lang.IllegalStateException: Async result for handler [public org.springframework.web.context.request.async.DeferredResult> nl.bioprodict.blast.api.PollController.poll(java.lang.String)] was not set during the specified timeToWait=25000 at org.springframework.util.Assert.state(Assert.java:392) at org.springframework.test.web.servlet.DefaultMvcResult.getAsyncResult(DefaultMvcResult.java:143) at org.springframework.test.web.servlet.DefaultMvcResult.getAsyncResult(DefaultMvcResult.java:120) at org.springframework.test.web.servlet.request.MockMvcRequestBuilders.asyncDispatch(MockMvcRequestBuilders.java:235) at nl.bioprodict.blast.docs.PollControllerDocumentation.pollPending(PollControllerDocumentation.java:53) ...

我发现所有与此相关的 Spring 框架测试似乎都使用了模拟: https://github.com/spring-projects/spring-framework/blob/master/spring-web/src/test/java/org/springframework/web/context/request/async/WebAsyncManagerTimeoutTests.java

如何测试 DeferredResult timeoutResult 的正确处理？

Answer 1

在我的情况下，经过 spring 源代码并设置超时(10000 毫秒)并获得异步结果后，为我解决了这个问题，因为；

 mvcResult.getRequest().getAsyncContext().setTimeout(10000);
 mvcResult.getAsyncResult();

我的整个测试代码是；

MvcResult mvcResult = this.mockMvc.perform(
                                post("<SOME_RELATIVE_URL>")
                                .contentType(MediaType.APPLICATION_JSON)
                                .content(<JSON_DATA>))
                        ***.andExpect(request().asyncStarted())***
                            .andReturn();

***mvcResult.getRequest().getAsyncContext().setTimeout(10000);***
***mvcResult.getAsyncResult();***

this.mockMvc
    .perform(asyncDispatch(mvcResult))
    .andDo(print())
    .andExpect(status().isOk());

希望能帮助到你..