node.js - graphql.js : field is null even though resolver is returning value for sequilize query

Question

我有以下 graphql 架构，我正在尝试执行 businessUser 查询

type Query {
  businessUser(id: String!): BusinessUser
}

type BusinessUser {
  id: ID!,
  firstName: String,
  lastName: String,
  email: String,
  posts: [BusinessPostFormat]
}

type BusinessPostFormat {
  postId: Int,
  user: String,
  isActive: Boolean,
  postText: String
}

在我的解析器中，我将 Post 表与 businessPost 表连接起来以检索“isActive”列。当我打印出 Sequilize 返回的内容时，我看到我返回的正是应该映射到 BusinessPostFormat 类型的数据对象:

post {
    dataValues: 
     { postId: '188',
       postText: 'blah blah blah',
       user: 'userName',
       isActive: false },

但是，当我在 graphiql 中执行查询时，isActive 字段返回为空。如果我能看到解析器返回的正是 BusinessPostFormat 类型所期望的，我不明白为什么会发生这种情况？

解析器功能如下:

const resolvers = {
  Query: {
    businessUser(_, args) {
      return BusinessUser.findById(args.id);
    }
},
BusinessUser: {
    posts(businessUser) {
      return businessUser.getPosts({
        attributes: {
          include: [[Sequelize.literal('business_posts.is_active'), 'isActive']],
          exclude: ['business_user_id']
        },
        include: [{ model: BusinessPost, attributes: ['is_active'] }]
      })
    },
  }

Answer 1

也许您忽略了 Sequelize 使用实例 http://docs.sequelizejs.com/manual/tutorial/instances.html 的事实，也许这就是本例中缺少的事实。
像这样试试。

return Entries.findAll().then(entries => {
  return entries.map(e => e.get({ plain: true }));
})