sequelize.js - Sequelize 如何将复杂的原始查询转换为 Sequelize 查询

Question

我有这个原始 SQL 查询。

SELECT 
    restaurants.name AS restaurant,
    ROUND((6371 * ACOS(COS(RADIANS(6.9271)) * COS(RADIANS(restaurants.latitude)) *
    COS(RADIANS(restaurants.longitude) - RADIANS(79.8612)) + SIN(RADIANS(6.9271)) *
    SIN(RADIANS(restaurants.latitude)))),
            2) AS distance,
    dishes.price
FROM
    restaurants
        INNER JOIN
    dishes ON restaurants.id = dishes.restaurantId
WHERE
    restaurants.status = TRUE
ORDER BY distance
LIMIT 200;

我确实想将此查询转换为 Sequelize 查询。
我到目前为止所做的是

const data = await db.restaurant.findAll({
      attributes: ['name'],
      include: [{ model: db.dish, attributes: ['price'] }],
      where: {
        status: true,
      },
      limit: 200,
    });

我如何将这个 距离 添加到我的查询中？

Answer 1

您可以使用 sequelize.literal() 来包含半正弦距离 -

attributes: [
  'name',
  [sequelize.literal(`
    ROUND((6371 * ACOS(COS(RADIANS(6.9271)) * COS(RADIANS(restaurants.latitude)) *
    COS(RADIANS(restaurants.longitude) - RADIANS(79.8612)) + SIN(RADIANS(6.9271)) *
    SIN(RADIANS(restaurants.latitude)))), 2)
  `, 'distance'],
],