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node.js - 如何在 PostgreSQL GEOMETRY 字段上创建空间索引?

转载 作者:行者123 更新时间:2023-12-03 22:16:46 25 4
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我正在使用 PostgreSQL 和 PostGIS 来处理表中的地理坐标。如何在 GEOMETRY(POINT) 上创建空间索引type 字段以提高基于距离的性能 ST_DWithin询问?
我正在使用迁移来创建索引。

最佳答案

对于几何,建议使用 gist 索引,例如

CREATE INDEX idx_any_label ON mytable USING gist (geom_column);
数据样本(50k 随机点):
CREATE TABLE t (geom geometry(point,4326));
INSERT INTO t
SELECT ('SRID=4326;POINT('||floor(random() * 50)||' ' ||floor(random() * 50) ||')')
FROM generate_series(1,50000);
没有索引的查询计划:
EXPLAIN ANALYSE
SELECT * FROM t
WHERE ST_DWithin('SRID=4326;POINT(1 1)',geom,1);

Seq Scan on t (cost=0.00..1252068.48 rows=5 width=32) (actual time=122.091..144.137 rows=98 loops=1)
Filter: st_dwithin('0101000020E6100000000000000000F03F000000000000F03F'::geometry, geom, '1'::double precision)
Rows Removed by Filter: 49902
Planning Time: 0.083 ms
JIT:
Functions: 2
Options: Inlining true, Optimization true, Expressions true, Deforming true
Timing: Generation 0.387 ms, Inlining 83.228 ms, Optimization 30.947 ms, Emission 7.626 ms, Total 122.187 ms
Execution Time: 186.107 ms
带有要点索引的查询计划
CREATE INDEX idx_t_geom ON t USING gist (geom);

EXPLAIN ANALYSE
SELECT * FROM t
WHERE ST_DWithin('SRID=4326;POINT(1 1)',geom,1);
QUERY PLAN
--------------------------------------------------------------------------------------------------------------------------------
Bitmap Heap Scan on t (cost=4.98..2119.16 rows=5 width=32) (actual time=0.086..0.367 rows=98 loops=1)
Filter: st_dwithin('0101000020E6100000000000000000F03F000000000000F03F'::geometry, geom, '1'::double precision)
Rows Removed by Filter: 83
Heap Blocks: exact=139
-> Bitmap Index Scan on idx_t_geom (cost=0.00..4.98 rows=77 width=0) (actual time=0.063..0.064 rows=181 loops=1)
Index Cond: (geom && st_expand('0101000020E6100000000000000000F03F000000000000F03F'::geometry, '1'::double precision))
Planning Time: 0.291 ms
Execution Time: 2.237 ms
演示: db<>fiddle

关于node.js - 如何在 PostgreSQL GEOMETRY 字段上创建空间索引?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/67805007/

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