python - 如何将大列表拆分成行？

Question

我的 list 有问题。我的任务是生成包含 10 个较小列表和 10 个随机数的随机列表的大列表。我有一个正确的代码在一个大列表中生成 10x 随机列表，但现在我需要将每个较小的列表分开，因为每个列表都必须在新行中。

这是我的代码:

def generate_random_number_list_10(len_of_elements):
single_list_of_10_random_numbers=[]
for _variable_1 in range (len_of_elements):
    random_number=random.randint(1,100)
    single_list_of_10_random_numbers.append(random_number)
return single_list_of_10_random_numbers

def generate_random_number_list_10x10_1(amount_of_lists):
main_list=[]
for _variable_1 in range (amount_of_lists):
    singlelist=generate_random_number_list_10(5)
    main_list.append(singlelist)
print(main_list)
generate_random_number_list_10x10_1(10)

这是我的结果:

[[45, 35, 90, 12, 13, 80, 33, 17, 50, 47], [33, 92, 55, 26, 60, 51, 78, 62, 35, 3], [87, 79, 4, 10, 57, 8, 59, 75, 59, 85], [33, 15, 10, 100, 79, 74, 57, 46, 14, 37], [93, 15, 29, 35, 54, 24, 24, 39, 21, 62], [55, 90, 8, 33, 6, 29, 19, 5, 97, 93], [51, 27, 14, 18, 45, 29, 83, 94, 34, 91], [66, 92, 40, 36, 72, 46, 77, 77, 89, 64], [89, 84, 36, 14, 96, 81, 57, 65, 51, 56], [97, 100, 94, 58, 26, 18, 6, 1, 88, 46]]

但我需要这样的东西:

[45, 35, 90, 12, 13, 80, 33, 17, 50, 47]
[33, 92, 55, 26, 60, 51, 78, 62, 35, 3]
etc...

Answer 1

您可以打开它们并使用 sep print 中的参数.

print(*list_of_lists,sep='\n')

[45, 35, 90, 12, 13, 80, 33, 17, 50, 47]
[33, 92, 55, 26, 60, 51, 78, 62, 35, 3]
[87, 79, 4, 10, 57, 8, 59, 75, 59, 85]
[33, 15, 10, 100, 79, 74, 57, 46, 14, 37]
[93, 15, 29, 35, 54, 24, 24, 39, 21, 62]
[55, 90, 8, 33, 6, 29, 19, 5, 97, 93]
[51, 27, 14, 18, 45, 29, 83, 94, 34, 91]
[66, 92, 40, 36, 72, 46, 77, 77, 89, 64]
[89, 84, 36, 14, 96, 81, 57, 65, 51, 56]
[97, 100, 94, 58, 26, 18, 6, 1, 88, 46]