jQuery .inArray() 总是 true？

Question

我正在尝试使用 inarray 但它总是返回 true？有任何想法吗？ (所有 li 均已显示)

$("#select-by-color-list li").hide();

// get the select
var $dd = $('#product-variants-option-0');

if ($dd.length > 0) { // make sure we found the select we were looking for

    // save the selected value
    var selectedVal = $dd.val();

    // get the options and loop through them
    var $options = $('option', $dd);
    var arrVals = [];
    $options.each(function(){
        // push each option value and text into an array
        arrVals.push({
            val: $(this).val(),
            text: $(this).text()
        });
    });




};

//This is where it is returning true...


if($.inArray('Aqua', arrVals)) {
    $("#select-by-color-list li#aqua").show();
    };
    if($.inArray('Army', arrVals)) {
    $("#select-by-color-list li#army").show();
    };

Answer 1

你需要这样做:

if( $.inArray('Aqua', arrVals) > -1 ) {

或者这个:

if( $.inArray('Aqua', arrVals) !== -1 ) {

The $.inArray() method返回基于 0 的项目索引。如果没有项目，则返回 -1，if() 语句会将其视为 true。

来自文档:

Because JavaScript treats 0 as loosely equal to false (i.e. 0 == false, but 0 !== false), if we're checking for the presence of value within array, we need to check if it's not equal to (or greater than) -1.

<小时/>

编辑:不要将两个值作为对象推送到数组中，而只需使用其中一个值，这样您就有了一个字符串数组，可以从中构建多个选择器。

一种方法是这样的:

  // Create an Array from the "value" or "text" of the select options
var arrVals = $.map( $dd[0].options, function( opt, i ){
    return opt.value || opt.text;
});

  // Build a multiple selector by doing a join() on the Array.
$( "#" + arrVals.join(',#') ).show();

如果数组看起来像:

['Army','Aqua','Bread'];

生成的选择器将如下所示:

$( "#Army,#Aqua,#Bread" ).show();