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java - 如何使用 groupBy 创建一个值为 BigDecimal 字段平均值的 map ?

转载 作者:行者123 更新时间:2023-12-03 21:47:14 25 4
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我有以下类(class):

final public class Person {

private final String name;
private final String state;
private final BigDecimal salary;

public Person(String name, String state, BigDecimal salary) {
this.name = name;
this.state = state;
this.salary = salary;
}

//getters omitted for brevity...
}

我想创建一个 map ,列出各州的平均工资。我如何使用 Java8 流来做到这一点?我尝试在 groupBy 上使用下游收集器,但无法以优雅的方式使用。

我做了以下工作,但看起来很丑陋:

Stream.of(p1,p2,p3,p4).collect(groupingBy(Person::getState, mapping(d -> d.getSalary(), toList())))
.forEach((state,wageList) -> {
System.out.print(state+"-> ");
final BigDecimal[] wagesArray = wageList.stream()
.map(bd -> new BigDecimal[]{bd, BigDecimal.ONE})
.reduce((a, b) -> new BigDecimal[]{a[0].add(b[0]), a[1].add(BigDecimal.ONE)})
.get();
System.out.println(wagesArray[0].divide(wagesArray[1])
.setScale(2, RoundingMode.CEILING));
});

有没有更好的办法?

最佳答案

这是一个仅使用 BigDecimal 算法的完整示例,并展示了如何实现自定义收集器

import java.math.BigDecimal;
import java.util.Collections;
import java.util.Map;
import java.util.Set;
import java.util.function.BiConsumer;
import java.util.function.BinaryOperator;
import java.util.function.Function;
import java.util.function.Supplier;
import java.util.stream.Collector;
import java.util.stream.Collectors;
import java.util.stream.Stream;

public final class Person {

private final String name;
private final String state;
private final BigDecimal salary;

public Person(String name, String state, BigDecimal salary) {
this.name = name;
this.state = state;
this.salary = salary;
}

public String getName() {
return name;
}

public String getState() {
return state;
}

public BigDecimal getSalary() {
return salary;
}

public static void main(String[] args) {
Person p1 = new Person("John", "NY", new BigDecimal("2000"));
Person p2 = new Person("Jack", "NY", new BigDecimal("3000"));
Person p3 = new Person("Jane", "GA", new BigDecimal("1500"));
Person p4 = new Person("Jackie", "GA", new BigDecimal("2500"));

Map<String, BigDecimal> result =
Stream.of(p1, p2, p3, p4).collect(
Collectors.groupingBy(Person::getState,
Collectors.mapping(Person::getSalary,
new AveragingCollector())));
System.out.println("result = " + result);

}

private static class AveragingCollector implements Collector<BigDecimal, IntermediateResult, BigDecimal> {
@Override
public Supplier<IntermediateResult> supplier() {
return IntermediateResult::new;
}

@Override
public BiConsumer<IntermediateResult, BigDecimal> accumulator() {
return IntermediateResult::add;
}

@Override
public BinaryOperator<IntermediateResult> combiner() {
return IntermediateResult::combine;
}

@Override
public Function<IntermediateResult, BigDecimal> finisher() {
return IntermediateResult::finish
}

@Override
public Set<Characteristics> characteristics() {
return Collections.emptySet();
}
}

private static class IntermediateResult {
private int count = 0;
private BigDecimal sum = BigDecimal.ZERO;

IntermediateResult() {
}

void add(BigDecimal value) {
this.sum = this.sum.add(value);
this.count++;
}

IntermediateResult combine(IntermediateResult r) {
this.sum = this.sum.add(r.sum);
this.count += r.count;
return this;
}

BigDecimal finish() {
return sum.divide(BigDecimal.valueOf(count), 2, BigDecimal.ROUND_HALF_UP);
}
}
}

如果您接受将 BigDecimal 值转换为双倍(恕我直言,对于平均工资来说,这是完全可以接受的),您可以使用

Map<String, Double> result2 =
Stream.of(p1, p2, p3, p4).collect(
Collectors.groupingBy(Person::getState,
Collectors.mapping(Person::getSalary,
Collectors.averagingDouble(BigDecimal::doubleValue))));

关于java - 如何使用 groupBy 创建一个值为 BigDecimal 字段平均值的 map ?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43793001/

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