typescript - 如何省略错误 : [ts] The inferred type of references an inaccessible 'this' type. 需要类型注释

Question

我想创建非常漂亮、流畅的 typescript api，但我得到了
错误:

[ts] The inferred type of 'firstLevelFunction' references an inaccessible 'this' type. A type annotation is necessary.

我的类(class)架构:

class SomeClassAPI { 

    // in my case (on the picture at bottom)
    // 'firstLevelFunction(...)' equal 'replace(...)' method ,
    // from class CodeTransform  )
    public firstLevelFunction() { 
        const self = this; // ERROR
        // const self = this as any; // OK but not typechecking

        return {
            secondLevelFunction() {
                return {
                    thirdLevelFunction() {
                        // ....
                    }
                }
            }
        }
    }
}

只有当我使用 'thirdLevelFunction' 做 api 时，我才会得到这个东西。
我怎样才能忽略这个错误 ?

我的 tsconfig.json

{
    "compileOnSave": true,
    "compilerOptions": {
        "declaration": true,
        "experimentalDecorators": true,
        "emitDecoratorMetadata": true,
        "allowSyntheticDefaultImports": true,
        "importHelpers": true,
        "module": "commonjs",
        "skipLibCheck": true,
        "sourceMap": true,
        "target": "es5",
        "typeRoots": [
            "node_modules/@types"
        ],
        "lib": [
            "dom",
            "es2015"
        ],
        "types": [
            "node"
        ],
        "rootDir": "./src",
        "outDir": "dist"
    },
    "include": [
        "src/**/*"
    ],
    "exclude": [
        "node_modules",
        "preview",
        "docs",
        "dist",
        "bundle",
        "example",
        "examples",
        "tests",
        "tmp-src"
    ]
}

这是错误在 vscode 中的样子:



我在用:

typescript 2.6.2

vscode 1.21.1

mac osx 10.13.3

Answer 1

我刚刚收到此错误消息。
当您明确指定函数返回值的类型时，它就会消失:public replace: any() {...}我猜 TS 无法推断出这种特定情况下的返回类型。