python-3.x - 使用 pathlib 创建新文件夹并将文件写入其中

Question

我正在做这样的事情:

import pathlib

p = pathlib.Path("temp/").mkdir(parents=True, exist_ok=True)

with p.open("temp."+fn, "w", encoding ="utf-8") as f:
    f.write(result)

Error message: AttributeError: 'NoneType' object has no attribute 'open'

显然，根据错误信息， mkdir返回 None .

Jean-Francois Fabre 提出了这样的修正:

p = pathlib.Path("temp/")
p.mkdir(parents=True, exist_ok=True)

with p.open("temp."+fn, "w", encoding ="utf-8") as f:
    ...

这触发了一条新的错误消息:

File "/Users/user/anaconda/lib/python3.6/pathlib.py", line 1164, in open opener=self._opener)
TypeError: an integer is required (got type str)

Answer 1

你可以试试:

p = pathlib.Path("temp/")
p.mkdir(parents=True, exist_ok=True)
fn = "test.txt" # I don't know what is your fn
filepath = p / fn
with filepath.open("w", encoding ="utf-8") as f:
    f.write(result)

您不应该将字符串作为路径。这是你的对象 filepath有方法 open .

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