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iphone - 将应用程序部署到越狱的 iPhone 后,GDB 会出现奇怪的行为

转载 作者:行者123 更新时间:2023-12-03 21:05:49 24 4
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我正在尝试创建一个应用程序,通过 NSTask 向 GDB 发送命令并将输出定向到 UITextView。它在 Mac(iOS 模拟器)上运行良好。然而,当部署到实际设备(iPhone)上时,在命令“info registers”之后并不会显示任何寄存器,代码如下:

 - (void)viewDidLoad
{
self.title = @"GDB";

NSLog(@"Pid for GDB execution is :%@", pid);

UIBarButtonItem *btnClicked = [[UIBarButtonItem alloc]
initWithTitle:@"Commands"
style:UIBarButtonItemStyleBordered
target:self
action:@selector(btnClicked:)];
self.navigationItem.rightBarButtonItem = btnClicked;
[btnClicked release];


stringInput = @"info registers";



task = [[NSTask alloc] init];
[task setLaunchPath: @"/usr/bin/gdb"];


arguments;
arguments = [NSArray arrayWithObjects:@"abc", pid, nil];
[task setArguments: arguments];




//
dataInput = [stringInput dataUsingEncoding:NSUTF8StringEncoding];



outputPipe;
outputPipe = [NSPipe pipe];
[task setStandardOutput: outputPipe];

//
inputPipe;
inputPipe = [NSPipe pipe];
[task setStandardInput:inputPipe];


taskOutput;
taskOutput = [outputPipe fileHandleForReading];

//
taskInput;
taskInput = [inputPipe fileHandleForWriting];



[task launch];


[[[task standardInput] fileHandleForWriting] writeData:dataInput];
close([taskInput fileDescriptor]);


dataOutput;
dataOutput = [taskOutput readDataToEndOfFile];




NSString *stringOutput;
stringOutput = [[NSString alloc] initWithData: dataOutput encoding: NSUTF8StringEncoding];
NSLog (@"GDB Output:\n%@", stringOutput);

//NSLog(@"GDB Input:\n@", stringInput);





//[string release];
[task release];
[arguments release];

textView = [[UITextView alloc]initWithFrame:CGRectMake(8,17,330,440)];


textView.editable=NO;
textView.scrollEnabled=YES;
[self.view addSubview:textView];

textView.text = [textView.text stringByAppendingString:stringOutput];

[super viewDidLoad];

}

IOS 模拟器上的输出如下所示(x86 寄存器)

enter image description here

实际设备(iPhone)上的输出如下所示:

enter image description here

在 iPhone 上运行时的构建输出如下所示:

RE:Notice: Launching: com.apple.gdb
abc: No such file or directory
//420: No such file or directory
Unable to access task for process-id 420: (os/kern) failure.
The program has no registers now.
2011-08-29 09:10:05.923 TableViewController_09[421:507] GDB Output:
GNU gdb 6.3.50.20050815-cvs (Fri May 20 08:08:42 UTC 2011)
Copyright 2004 Free Software Foundation, Inc.
GDB is free software, covered by the GNU General Public License, and you are
welcome to change it and/or distribute copies of it under certain conditions.
Type "show copying" to see the conditions.
There is absolutely no warranty for GDB. Type "show warranty" for details.
This GDB was configured as "--host=arm-apple-darwin9 --target="...
(gdb) (gdb)

作为旁注,我什至尝试添加参数 -arch armv7*。仍然无法附加到指定的进程。

编辑:我可能已经找到了我的痛苦的根源。当我尝试通过应用程序在 iPhone 中调用 gdb 时,这出现在控制台中:

Sep  8 11:13:26 unknown sandboxd[2138] <Notice>: gdb(2137) deny mach-priv-task-port

Process: gdb [2137]
Path: /usr/bin/gdb
Load Address: 0x1000
Identifier: gdb
Version: ??? (1.0)
Code Type: ARM (Native)
Parent Process: TableViewController_09 [2135]

Date/Time: 2011-09-08 11:13:25.948 +0800
OS Version: iPhone OS 4.3.3 (8J2)
Report Version: 104

Backtrace:
0 libsystem_kernel.dylib 0x36223c8c task_for_pid + 8
1 gdb 0x001e4428 macosx_child_attach + 44 (macosx-nat-inferior.c:1781)
2 gdb 0x00082f18 attach_command + 116 (infcmd.c:3089)
3 gdb 0x000a3788 catch_command_errors + 100 (exceptions.c:540)
4 gdb 0x000a53e4 captured_main + 2632 (main.c:888)
5 gdb 0x000a3838 catch_errors + 104 (exceptions.c:525)
6 gdb 0x000a4988 gdb_main + 56 (main.c:1033)
7 gdb 0x0000224c main + 40 (gdb.c:36)
8 gdb 0x0000217c _start + 312
9 gdb 0x00002018 start + 24
10 gdb 0x001e3dac macosx_lookup_task + 1596 (macosx-nat-inferior.c:1522)

Binary Images:
0x1000 - 0x2fbf5b +gdb arm /usr/bin/gdb
0x36214000 - 0x3622bfff libsystem_kernel.dylib armv7 <a06ec84e53bf32098b63c0caebdb45b6> /usr/lib/system/libsystem_kernel.dylib

如果有人知道解决此问题的方法,请分享。我已经寻找解决方案好几个星期了,但没有成功......

最佳答案

除非您对设备进行越狱,否则您无法在设备本身上运行 gdb

关于iphone - 将应用程序部署到越狱的 iPhone 后,GDB 会出现奇怪的行为,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/7225264/

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