iphone - 如何将带有用户名和密码的 JSON 对象发送到 iPhone 中的 RESET 登录 Web 服务？

Question

我必须使用 JSON 对象发送用户名和密码才能登录 REST Web 服务。我已经在android中使用以下代码完成了。

HttpClient client = new DefaultHttpClient();
                    String responseBody;
                    JSONObject jObj = new JSONObject();

                    try
                    {
                        HttpPost post = new HttpPost("http://localhost:8080/MTA/login");
                        jObj.put("email", "user@email.com");
                        jObj.put("password", "password12345");

                        StringEntity se = new StringEntity(jObj.toString());  

                        post.setEntity(se);
                        post.setHeader(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));
                        post.setHeader("Content-type", "application/json");
                        System.out.println("webservice request executing");

                        ResponseHandler responseHandler = new BasicResponseHandler();
                        responseBody = client.execute(post, responseHandler);

                        System.out.println("Response : " + responseBody);
                        /* 
                         * You can work here on your responseBody
                         * if it's a simple String or XML/JSON response
                         */

                    }
                    catch(Exception e)
                    {
                        System.out.println("Exception : " + e);
                    }

我必须在 iOS 中做同样的事情。我在 iOS 中可以做什么？

Answer 1

我正在使用 Ge.tt API，为了登录，我正在执行以下操作:

NSString *email = @"Some email";
NSString *password = @"Some password"
NSString *apikey = @"some api key";
NSString *loginURL = @"http://open.ge.tt/1/users/login";

NSURL *url = [NSURL URLWithString:loginURL];

NSString *JSONString = [NSString stringWithFormat:@"{\"apikey\":\"%@\",\"email\":\"%@\",\"password\":\"%@\"}", apikey, email, password];

NSData *JSONBody = [JSONString dataUsingEncoding:NSUTF8StringEncoding];

NSMutableURLRequest *loginRequest = [[NSMutableURLRequest alloc] initWithURL:url];
loginRequest.HTTPMethod = @"POST";
loginRequest.HTTPBody = JSONBody;

NSOperationQueue *queue = [NSOperationQueue new];

[NSURLConnection sendAsynchronousRequest:loginRequest 
                                   queue:queue 
                       completionHandler:^(NSURLResponse *response, NSData *data, NSError *error){

                                        // Manage the response here.

                                        }];