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file - 在php中使用multipart/form-data请求发送文件

转载 作者:行者123 更新时间:2023-12-03 20:37:39 49 4
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我将图像资源存储在变量中,我需要使用其 http API 和 PHP 将其发送到服务器。我必须发送内容类型为 multipart/form-data 的请求。所以,我需要发出类似的请求,就像发送带有文件输入和 enctype=multipart/form-data 属性的表单一样。
我试过这个:

<?php
$url = 'here_is_url_for_web_API';
$input = fopen('delfin.jpg','r');
$header = array('Content-Type: multipart/form-data');
$resource = curl_init();
curl_setopt($resource, CURLOPT_URL, $url);
curl_setopt($resource, CURLOPT_USERPWD, "user:password");
curl_setopt($resource, CURLOPT_HTTPAUTH, CURLAUTH_ANYSAFE);
curl_setopt($resource, CURLOPT_HTTPHEADER, $header);
curl_setopt($resource, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($resource, CURLOPT_BINARYTRANSFER, true );
curl_setopt($resource, CURLOPT_INFILESIZE, 61631);
curl_setopt($resource, CURLOPT_INFILE, $input);
$result = curl_exec($resource);
curl_close($resource);
var_dump($result);
?>

我不知道响应应该是什么样子,但这会返回:
http 状态 405
并且报错为:请求的资源不允许指定的HTTP方法()。

最佳答案

在带有 curl 的 POST 内容中使用 multipart/form-data 和边界。

$filenames = array("/tmp/1.jpg", "/tmp/2.png");

$files = array();
foreach ($filenames as $f){
$files[$f] = file_get_contents($f);
}

// more fields for POST request
$fields = array("f1"=>"value1", "another_field2"=>"anothervalue");

$url = "http://example.com/upload";

$curl = curl_init();

$url_data = http_build_query($data);

$boundary = uniqid();
$delimiter = '-------------' . $boundary;

$post_data = build_data_files($boundary, $fields, $files);

curl_setopt_array($curl, array(
CURLOPT_URL => $url,
CURLOPT_RETURNTRANSFER => 1,
CURLOPT_MAXREDIRS => 10,
CURLOPT_TIMEOUT => 30,
//CURLOPT_HTTP_VERSION => CURL_HTTP_VERSION_1_1,
CURLOPT_CUSTOMREQUEST => "POST",
CURLOPT_POST => 1,
CURLOPT_POSTFIELDS => $post_data,
CURLOPT_HTTPHEADER => array(
//"Authorization: Bearer $TOKEN",
"Content-Type: multipart/form-data; boundary=" . $delimiter,
"Content-Length: " . strlen($post_data)
)
));

//
$response = curl_exec($curl);

$info = curl_getinfo($curl);
//echo "code: ${info['http_code']}";

//print_r($info['request_header']);

var_dump($response);
$err = curl_error($curl);

echo "error";
var_dump($err);
curl_close($curl);

function build_data_files($boundary, $fields, $files){
$data = '';
$eol = "\r\n";

$delimiter = '-------------' . $boundary;

foreach ($fields as $name => $content) {
$data .= "--" . $delimiter . $eol
. 'Content-Disposition: form-data; name="' . $name . "\"".$eol.$eol
. $content . $eol;
}

foreach ($files as $name => $content) {
$data .= "--" . $delimiter . $eol
. 'Content-Disposition: form-data; name="' . $name . '"; filename="' . $name . '"' . $eol
//. 'Content-Type: image/png'.$eol
. 'Content-Transfer-Encoding: binary'.$eol;

$data .= $eol;
$data .= $content . $eol;
}
$data .= "--" . $delimiter . "--".$eol;

return $data;
}

在此处查看完整示例: https://gist.github.com/maxivak/18fcac476a2f4ea02e5f80b303811d5f

关于file - 在php中使用multipart/form-data请求发送文件,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/17862004/

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