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gcc - 使用 gcc 为 32 位体系结构编译的 C 程序的意外退出代码

转载 作者:行者123 更新时间:2023-12-03 20:27:34 25 4
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我编写了一个简单的 C 程序,并为 32 位架构编译了它。

但是当我运行它时,我发现了意想不到的结果。

#include <stdio.h>

int foo(int n) {
int sum=0;
int i;
if (n <= 1 || n >= 0x1000)
return n;
for (i=0; i<= n; i++) {
sum = sum + i;
}
return foo(sum);
}

int main(int argc, char** argv) {
int n;
n = foo(200);
printf("\n\n main about to return %d \n\n", n);
return n;
}

➜  wbench  gcc -o test.elf test.c -m32 -fno-stack-protector -mpreferred-stack-boundary=2 -Wall
➜ wbench ./test.elf

main about to return 20100


➜ wbench echo $?
132

我在期待 20100是返回值,由 main 函数打印。

但是,我收到了 132作为退出代码。

我使用 GDB 验证了 20100eax 中的值在 main 即将返回时注册。

➜  wbench  gdb -q test.elf
gdb-peda$ b *main+44
Breakpoint 1 at 0x8048492
gdb-peda$ r

main about to return 20100

Breakpoint 1, 0x08048492 in main ()

0x8048489 <main+35>: call 0x80482f0 <printf@plt>
0x804848e <main+40>: mov eax,DWORD PTR [ebp-0x4]
0x8048491 <main+43>: leave
=> 0x8048492 <main+44>: ret
0x8048493: xchg ax,ax



gdb-peda$ p/d $eax
$1 = 20100
gdb-peda$ c
[Inferior 1 (process 32172) exited with code 0204]
Warning: not running or target is remote
gdb-peda$ p/d 0204
$2 = 132

我什至验证了当控制权转移回 __libc_start_main 时和 exit正在调用函数, 20100被作为参数推送到 exit() .

gdb-peda$ r
main returning 20100
Breakpoint 1, 0x08048492 in main ()

gdb-peda$ finish
=> 0xf7e1ca83 <__libc_start_main+243>: mov DWORD PTR [esp],eax
0xf7e1ca86 <__libc_start_main+246>: call 0xf7e361e0 <exit>
0xf7e1ca8b <__libc_start_main+251>: xor ecx,ecx
gdb-peda$ si
=> 0xf7e1ca86 <__libc_start_main+246>: call 0xf7e361e0 <exit>
0xf7e1ca8b <__libc_start_main+251>: xor ecx,ecx
gdb-peda$ x/wd $esp
0xffffd5c0: 20100

这可能是什么原因?

我不认为退出代码 132这里与 SIGILL有关因为当我将硬编码参数更改为 foo() 时来自 2002 ,退出码改为 172其中预期的退出代码是 26796 .

最佳答案

看起来您正在做的事情无效,因为您只有 8 位可以返回到操作系统。

假设您正在链接 libc :

When a program exits, it can return to the parent process a small amount of information about the cause of termination, using the exit status. This is a value between 0 and 255 that the exiting process passes as an argument to exit.



如其文档 here 中所述.同样相关的是这一行:

Warning: Don’t try to use the number of errors as the exit status. This is actually not very useful; a parent process would generally not care how many errors occurred. Worse than that, it does not work, because the status value is truncated to eight bits. Thus, if the program tried to report 256 errors, the parent would receive a report of 0 errors—that is, success.

关于gcc - 使用 gcc 为 32 位体系结构编译的 C 程序的意外退出代码,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31815346/

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