java - JAXB Java 生成 XML，为什么小写？

Question

当我运行这段代码时:

import javax.xml.bind.JAXBContext;
import javax.xml.bind.Marshaller;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlRootElement;

public class JavaToXMLDemo {
  public static void main(String[] args) throws Exception {
    JAXBContext context = JAXBContext.newInstance(Employee.class);

    Marshaller m = context.createMarshaller();
    m.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);

    Employee object = new Employee();
    object.setCode("CA");
    object.setName("Cath");
    object.setSalary(300);

    m.marshal(object, System.out);

  }
}

@XmlRootElement
@XmlAccessorType(XmlAccessType.FIELD)
class Employee {
  private String code;

  private String name;

  private int salary;

  public String getCode() {
    return code;
  }

  public void setCode(String code) {
    this.code = code;
  }

  public String getName() {
    return name;
  }

  public void setName(String name) {
    this.name = name;
  }

  public int getSalary() {
    return salary;
  }

  public void setSalary(int population) {
    this.salary = population;
  }
}

我明白了

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<employee>
    <code>CA</code>
    <name>Cath</name>
    <salary>300</salary>
</employee>

哪个是正确的，所以我的问题是为什么它会将 Employee 更改为 employee？是否可以使用大写字母 E 而不是员工打印？

这才是我真正想要的:

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<Employee>
    <code>CA</code>
    <name>Cath</name>
    <salary>300</salary>
</Employee>

谢谢!

Answer 1

您看到的行为是标准 JAXB (JSR-222) 的结果XML 名称到 Java 名称的转换算法。

您可以使用@XmlRootElement 注释来指定名称:

@XmlRootElement(name="Employee")
@XmlAccessorType(XmlAccessType.FIELD)
class Employee {
    ...
}

我是 EclipseLink JAXB (MOXy) lead，我们有一个扩展，允许您覆盖您可能感兴趣的默认名称转换算法:

• http://blog.bdoughan.com/2011/05/overriding-jaxbs-name-mangling.html