iphone - 将 subview 显示为弹出窗口时出现问题

Question

我想在弹出窗口中显示 View 的 subview 。详细说明一下，

我有一个 mainViewController。我在这个 mainViewController 中有一个 subview “songListView”。我在 mainViewController 本身中有一个名为“列表”的按钮。我想在单击“列表”按钮时在弹出窗口中显示歌曲 ListView 。

那么，我该怎么做。

Answer 1

您可以使用以下代码作为从 UIButton 显示 PopOver 的引用

-(void) buttonAction:(id)sender {
   //build our custom popover view
   UIViewController* popoverContent = [[UIViewController alloc]
                  init];
   UIView* popoverView = [[UIView alloc]
                  initWithFrame:CGRectMake(0, 0, 200, 300)];
   popoverView.backgroundColor = [UIColor greenColor];
   popoverContent.view = popoverView;

   //resize the popover view shown
   //in the current view to the view's size
   popoverContent.contentSizeForViewInPopover =
                  CGSizeMake(200, 300);

   //create a popover controller
   self.popoverController = [[UIPopoverController alloc]
               initWithContentViewController:popoverContent];

   //present the popover view non-modal with a
   //refrence to the button pressed within the current view
   [self.popoverController presentPopoverFromRect:popoverButton.frame
               inView:self.view
               permittedArrowDirections:UIPopoverArrowDirectionAny
               animated:YES];

   //release the popover content
   [popoverView release];
   [popoverContent release];
}