python - 将列表转换为多值字典

Question

我有一个这样的列表:

pokemonList = ['Ivysaur', 'Grass', 'Poison', '', 'Venusaur', 'Grass', 'Poison', '', 'Charmander', 'Fire', ''...]

注意模式是'Pokemon name', 'its type', ''...next pokemon

口袋妖怪有单型和双型两种形式。我如何编写此代码，以便每个口袋妖怪( key )都将其各自的类型应用为它的值？

到目前为止我得到了什么:

types = ("", "Grass", "Poison", "Fire", "Flying", "Water", "Bug","Dark","Fighting", "Normal","Ground","Ghost","Steel","Electric","Psychic","Ice","Dragon","Fairy")
pokeDict = {}
    for pokemon in pokemonList:
        if pokemon not in types:
            #the item is a pokemon, append it as a key
        else:
            for types in pokemonList:
                #add the type(s) as a value to the pokemon

正确的字典应该是这样的:

{Ivysaur: ['Grass', 'Poison'], Venusaur['Grass','Poison'], Charmander:['Fire']}

Answer 1

只需迭代列表并适本地为字典构造项目..

current_poke = None
for item in pokemonList:
    if not current_poke:
        current_poke = (item, [])
    elif item:
        current_poke[1].append(item)
    else:
        name, types = current_poke
        pokeDict[name] = types
        current_poke = None