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python - 具有多索引的 Pandas 长格式到宽格式

转载 作者:行者123 更新时间:2023-12-03 20:17:34 28 4
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我有一个看起来像这样的数据框:

data.head()
Out[2]:
Area Area Id Variable Name Variable Id Year \
0 Argentina 9 Conservation agriculture area 4454 1982
1 Argentina 9 Conservation agriculture area 4454 1987
2 Argentina 9 Conservation agriculture area 4454 1992
3 Argentina 9 Conservation agriculture area 4454 1997
4 Argentina 9 Conservation agriculture area 4454 2002
Value Symbol Md
0 2.0
1 6.0
2 500.0

我想旋转以便 Variable Name是列, AreaYear是索引和 Value是值(value)观。对我来说最直观的方法是使用:
data.pivot(index=['Area', 'Year'], columns='Variable Name', values='Value)

但是我收到错误:
Traceback (most recent call last):
File "C:\Users\patri\Miniconda3\lib\site-packages\IPython\core\interactiveshell.py", line 2862, in run_code
exec(code_obj, self.user_global_ns, self.user_ns)
File "<ipython-input-4-4c786386b703>", line 1, in <module>
pd.concat(data_list).pivot(index=['Area', 'Year'], columns='Variable Name', values='Value')
File "C:\Users\patri\Miniconda3\lib\site-packages\pandas\core\frame.py", line 3853, in pivot
return pivot(self, index=index, columns=columns, values=values)
File "C:\Users\patri\Miniconda3\lib\site-packages\pandas\core\reshape\reshape.py", line 377, in pivot
index=MultiIndex.from_arrays([index, self[columns]]))
File "C:\Users\patri\Miniconda3\lib\site-packages\pandas\core\series.py", line 250, in __init__
data = SingleBlockManager(data, index, fastpath=True)
File "C:\Users\patri\Miniconda3\lib\site-packages\pandas\core\internals.py", line 4117, in __init__
fastpath=True)
File "C:\Users\patri\Miniconda3\lib\site-packages\pandas\core\internals.py", line 2719, in make_block
return klass(values, ndim=ndim, fastpath=fastpath, placement=placement)
File "C:\Users\patri\Miniconda3\lib\site-packages\pandas\core\internals.py", line 1844, in __init__
placement=placement, **kwargs)
File "C:\Users\patri\Miniconda3\lib\site-packages\pandas\core\internals.py", line 115, in __init__
len(self.mgr_locs)))
ValueError: Wrong number of items passed 119611, placement implies 2

我应该如何解释这个?我也试过另一种方式:
data.set_index(['Area', 'Variable Name', 'Year']).loc[:, 'Value'].unstack('Variable Name')

尝试获得相同的结果,但我收到此错误:
Traceback (most recent call last):
File "C:\Users\patri\Miniconda3\lib\site-packages\IPython\core\interactiveshell.py", line 2862, in run_code
exec(code_obj, self.user_global_ns, self.user_ns)
File "<ipython-input-5-222325ea01e1>", line 1, in <module>
pd.concat(data_list).set_index(['Area', 'Variable Name', 'Year']).loc[:, 'Value'].unstack('Variable Name')
File "C:\Users\patri\Miniconda3\lib\site-packages\pandas\core\series.py", line 2028, in unstack
return unstack(self, level, fill_value)
File "C:\Users\patri\Miniconda3\lib\site-packages\pandas\core\reshape\reshape.py", line 458, in unstack
fill_value=fill_value)
File "C:\Users\patri\Miniconda3\lib\site-packages\pandas\core\reshape\reshape.py", line 110, in __init__
self._make_selectors()
File "C:\Users\patri\Miniconda3\lib\site-packages\pandas\core\reshape\reshape.py", line 148, in _make_selectors
raise ValueError('Index contains duplicate entries, '
ValueError: Index contains duplicate entries, cannot reshape

数据有问题吗?我已经确认 Area 没有重复的组合, Variable Name , 和 Year在数据框的任何一行中,所以我认为不应该有任何重复的条目,但我可能是错的。鉴于这两种方法目前都不起作用,如何从长格式转换为宽格式?我查过答案 herehere ,但它们都是涉及某种类型 I 聚合的情况。

我试过使用 pivot_table像这样:
data.pivot_table(index=['Area', 'Year'], columns='Variable Name', values='Value')

但我认为正在进行某种类型的聚合,并且数据集中有很多缺失值导致此错误:
Traceback (most recent call last):
File "C:\Users\patri\Miniconda3\lib\site-packages\IPython\core\interactiveshell.py", line 2862, in run_code
exec(code_obj, self.user_global_ns, self.user_ns)
File "<ipython-input-7-77b28d2f0dbb>", line 1, in <module>
pd.concat(data_list).pivot_table(index=['Area', 'Year'], columns='Variable Name', values='Value')
File "C:\Users\patri\Miniconda3\lib\site-packages\pandas\core\reshape\pivot.py", line 136, in pivot_table
agged = grouped.agg(aggfunc)
File "C:\Users\patri\Miniconda3\lib\site-packages\pandas\core\groupby.py", line 4036, in aggregate
return super(DataFrameGroupBy, self).aggregate(arg, *args, **kwargs)
File "C:\Users\patri\Miniconda3\lib\site-packages\pandas\core\groupby.py", line 3468, in aggregate
result, how = self._aggregate(arg, _level=_level, *args, **kwargs)
File "C:\Users\patri\Miniconda3\lib\site-packages\pandas\core\base.py", line 435, in _aggregate
**kwargs), None
File "C:\Users\patri\Miniconda3\lib\site-packages\pandas\core\base.py", line 391, in _try_aggregate_string_function
return f(*args, **kwargs)
File "C:\Users\patri\Miniconda3\lib\site-packages\pandas\core\groupby.py", line 1037, in mean
return self._cython_agg_general('mean', **kwargs)
File "C:\Users\patri\Miniconda3\lib\site-packages\pandas\core\groupby.py", line 3354, in _cython_agg_general
how, alt=alt, numeric_only=numeric_only)
File "C:\Users\patri\Miniconda3\lib\site-packages\pandas\core\groupby.py", line 3425, in _cython_agg_blocks
raise DataError('No numeric types to aggregate')
pandas.core.base.DataError: No numeric types to aggregate

最佳答案

我认为您需要先转换列 Value到数字然后使用 pivot_table使用默认聚合函数 mean :

#if all float data saved as strings
data['Value'] = data['Value'].astype(float)
#if some bad data like strings and first method return value error
data['Value'] = pd.to_numeric(data['Value'], errors='coerce')
data.pivot_table(index=['Area', 'Year'], columns='Variable Name', values='Value')

或者:
data.groupby(['Area', 'Variable Name', 'Year'])[ 'Value'].mean().unstack('Variable Name')

关于python - 具有多索引的 Pandas 长格式到宽格式,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/47178861/

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