iphone - 向表中插入数据时出现问题

Question

sqlite3 *数据库； sqlite3_stmt *语句； NSString *dPath = [[[NSBundle mainBundle] resourcesPath] stringByAppendingPathComponent:@"UserData.sqlite"]; const char *dbpath = [dPath UTF8String]; //NSLog(@"%@",dbpath); //UserArray = [[NSMutableArray alloc]init];

if(sqlite3_open(dbpath, &database) == SQLITE_OK)
{

    NSString *insertSQL = [NSString stringWithFormat: @"INSERT INTO User (UserName,FullName,Email,PhoneNo) VALUES (\"%@\", \"%@\", \"%@\" ,\"%@\")",txtUserName.text,txtFullName.text ,txtEmail.text , txtPhoneNo.text];

    const char *insert_stmt = [insertSQL UTF8String];

    sqlite3_prepare_v2(database, insert_stmt, -1, &statement, NULL);

    if(sqlite3_step(statement)==SQLITE_DONE) 
    {
        txtUserName.text=@"";
        txtFullName.text=@"";
        txtEmail.text=@"";
        txtPhoneNo.text=@"";
        UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Add Record" message:@"Contact Added" delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil];    
        [alert show];
        [alert release];
        alert=nil;

    }
    else 
    {
        UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"record" message:@"record not created" delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil];   
        [alert show];
        [alert release];
        alert=nil;
    }


    // Release the compiled statement from memory
    sqlite3_finalize(statement);

    sqlite3_close(database);
}

->> 我正在尝试将数据插入表中。代码执行正常，但记录未添加到表中。所以请帮助我或这个问题..感谢您的回复。

Answer 1

尝试执行提交，因此将数据库设置为自动提交

// COMMIT
  const char *sql2 = "COMMIT TRANSACTION";
  sqlite3_stmt *commit_statement;
  if (sqlite3_prepare_v2(database, sql2, -1, &commit_statement, NULL) != SQLITE_OK) {
    NSAssert1(0, @"Error Message: '%s'.", sqlite3_errmsg(database));
  }
  success = sqlite3_step(commit_statement);
  if (success != SQLITE_DONE) {
    NSAssert1(0, @"Error Message: '%s'.", sqlite3_errmsg(database));
  }
}