iphone - 给定一组地理坐标，获取一个友好的位置名称？

Question

对于一组给定的地理坐标，是否有可能获得最接近的有意义的地标(例如街道交叉口)的人性化文本描述，例如通过 Google map 或其他第三方等网络服务？我正在使用 MapKit， 但我怀疑它有内置的东西 。 Turns out it does.

例如，我正在寻找最近的街道交叉口(实际上这是理想的)或任何类型的“地名”。诸如此类:

E Hastings St and Main St
128 W Cordova St
PNE Fairgrounds

Answer 1

所以我做了一个项目，遇到了这个问题...你可以引用CLPlacemark class reference在苹果开发者网页中。

这是我使用它的方式，我认为您还必须将 corelocation 库添加到项目中，就像我所做的那样。

#import <CoreLocation/CoreLocation.h>

现在在.h file:

添加 CLLocation 委托(delegate):<CLLocationManagerDelegate>

然后添加以下实例变量:

CLLocationManager *locationManager;
CLLocation *currentLocation;

现在在.m file:

-(void) viewDidLoad{
    locationManager = [[CLLocationManager alloc] init];
    locationManager.delegate = self;
    locationManager.distanceFilter = kCLDistanceFilterNone; // whenever we move, location is updated
    locationManager.desiredAccuracy = kCLLocationAccuracyBest; // get best current locaton coords
    locationManager.headingFilter = 1;
    [locationManager startUpdatingLocation];
    [locationManager startUpdatingHeading];
}

现在实现 CLLocationManager viewDidLoad之后的委托(delegate)方法方法，或之前，无论您喜欢哪种:

#pragma mark CLLocationManager Delegate
- (void)locationManager:(CLLocationManager *)manager didUpdateLocations:(NSArray *)locations {
    currentLocation = [locations objectAtIndex:0];
    [locationManager stopUpdatingLocation];
    NSLog(@"Detected Location : %f, %f", currentLocation.coordinate.latitude, currentLocation.coordinate.longitude);
    CLGeocoder *geocoder = [[CLGeocoder alloc] init] ;
    [geocoder reverseGeocodeLocation:currentLocation
                   completionHandler:^(NSArray *placemarks, NSError *error) {
                       if (error){
                           NSLog(@"Geocode failed with error: %@", error);
                           return;
                       }
                       CLPlacemark *placemark = [placemarks objectAtIndex:0];
                       NSLog(@"City = %@ : State = %@ : Country = %@ : Zip Code = %@", placemark.locality, placemark.administrativeArea, placemark.ISOcountryCode, placemark.postalCode);
                   }];
}

运行代码并确保如果您使用 iOS 模拟器，请务必通过单击控制台输出屏幕上方的箭头按钮来模拟位置。

它仅在您构建并运行项目后才会显示。

希望这对您有帮助:)

这是我得到的输出:

2013-08-02 20:39:46.935 PowerOneApp[3449:c07] Detected Location : 37.785834, -122.406417
2013-08-02 20:39:49.773 PowerOneApp[3449:c07] City = San Francisco : State = California : Country = US : Zip Code = 94115

编辑抱歉，当我写这个答案时，我意识到您想要更多精确的坐标。

这里:

#pragma mark CLLocationManager Delegate
- (void)locationManager:(CLLocationManager *)manager didUpdateLocations:(NSArray *)locations {
    currentLocation = [locations objectAtIndex:0];
    [locationManager stopUpdatingLocation];
    NSLog(@"Detected Location : %f, %f", currentLocation.coordinate.latitude, currentLocation.coordinate.longitude);
    CLGeocoder *geocoder = [[CLGeocoder alloc] init] ;
    [geocoder reverseGeocodeLocation:currentLocation
                   completionHandler:^(NSArray *placemarks, NSError *error) {
                       if (error){
                           NSLog(@"Geocode failed with error: %@", error);
                           return;
                       }
                       CLPlacemark *placemark = [placemarks objectAtIndex:0];
                       NSLog(@"%@", placemark.addressDictionary);
                       NSLog(@"%@", [placemark.addressDictionary valueForKey:@"Street"]);
                   }];
}

输出如下:

2013-08-02 20:44:26.052 PowerOneApp[3531:c07] Detected Location : 37.785834, -122.406417
2013-08-02 20:44:26.340 PowerOneApp[3531:c07] {
    City = "San Francisco";
    Country = "United States";
    CountryCode = US;
    FormattedAddressLines =     (
        "Apple Store, San Francisco",
        "1800 Ellis St",
        "San Francisco, CA  94115-4004",
        "United States"
    );
    Name = "Apple Store, San Francisco";
    PostCodeExtension = 4004;
    State = California;
    Street = "1800 Ellis St";
    SubAdministrativeArea = "San Francisco";
    SubLocality = "Union Square";
    SubThoroughfare = 1800;
    Thoroughfare = "Ellis St";
    ZIP = 94115;
}
2013-08-02 20:44:26.340 PowerOneApp[3531:c07] 1800 Ellis St

如您所见，有一个名为 addressDictionary 的属性返回 CLPlacemark 类拥有的所有属性。所以在这里，如果您熟悉 NSDictionary对象，我只是先输出整个字典，然后指定我想要记录的值。

希望这对您的确切问题有所帮助:)