sqlite - 连接表的SQLite错误

Question

我有以下表格：

PRAGMA foreign_keys = ON;

CREATE TABLE products(
    '_id' INTEGER PRIMARY KEY AUTOINCREMENT,
    'name' VARCHAR(20),
    'price' INTEGER
);

CREATE TABLE orders(
    '_id' INTEGER PRIMARY KEY AUTOINCREMENT,
    'order_number' INTEGER,
    'order_sum' INTEGER
);

CREATE TABLE ord_details(
    '_id' INTEGER PRIMARY KEY AUTOINCREMENT,
    'order_id' INTEGER,
    'product_id' INTEGER,
    'product_count' INTEGER,
    FOREIGN KEY (order_id) REFERENCES orders(_id) ON DELETE CASCADE ON UPDATE CASCADE,
    FOREIGN KEY (product_id) REFERENCES products(_id) ON DELETE CASCADE ON UPDATE CASCADE
);

CREATE TABLE ord_times(
    '_id' INTEGER PRIMARY KEY AUTOINCREMENT,
    'order_id' INTEGER,
    'start_t' TIMESTAMP DEFAULT CURRENT_TIMESTAMP,
    'end_t' TIMESTAMP DEFAULT CURRENT_TIMESTAMP,
    FOREIGN KEY (order_id) REFERENCES orders(_id) ON DELETE CASCADE ON UPDATE CASCADE
);

因此，在表中具有以下数据：

在“产品”表中

---------------------
1 | roll        | 100
2 | cheese      | 500
3 | burger      | 300
4 | mega burger | 550

在“订单”表中

-------------
1 | 11 | 600

在“ ord_details”表中

--------------
1 | 1 | 1 | 1
1 | 1 | 2 | 1

在“ ord_times”表中

--------------------------------------------------------
1 | 1 | 12/23/2013 12:24:38 PM | 12/23/2013  12:27:02 PM

当我执行此SQL命令时，它给出不正确的结果：

SELECT orders.order_number, products.name as prname, products.price, ord_details.product_count, orders.order_sum, ord_times.start_t, ord_times.end_t FROM orders 
LEFT JOIN ord_details ON orders._id=ord_details.order_id 
LEFT JOIN products ON ord_details.product_id=products._id
LEFT JOIN ord_times ON orders._id=ord_times.order_id

结果：

-----------------------------------------------------------------------------------
11 | roll        | 100 | 1 | 600 | 12/23/2013 12:24:38 PM | 12/23/2013  12:27:02 PM
11 | cheese      | 500 | 1 | 600 | 12/23/2013 12:24:38 PM | 12/23/2013  12:27:02 PM
11 | burger      | 300 | 0 | 600 | 12/23/2013 12:24:38 PM | 12/23/2013  12:27:02 PM
11 | mega burger | 550 | 0 | 600 | 12/23/2013 12:24:38 PM | 12/23/2013  12:27:02 PM

我期望如下结果：

-----------------------------------------------------------------------------------
11 | roll        | 100 | 1 | 600 | 12/23/2013 12:24:38 PM | 12/23/2013  12:27:02 PM
11 | cheese      | 500 | 1 | 600 | 12/23/2013 12:24:38 PM | 12/23/2013  12:27:02 PM

当我在sqlite-shell-win32-x86-3080200中正常执行此代码时：



但是在android中执行此SQL会返回错误的结果。
在这里插入代码：

INSERT INTO products (name, price) VALUES ("roll", 100);
INSERT INTO products (name, price) VALUES ("cheese", 500);
INSERT INTO products (name, price) VALUES ("burger", 300);
INSERT INTO products (name, price) VALUES ("mega burger", 550);
INSERT INTO orders (order_number, order_sum) VALUES (11, 600);
INSERT INTO ord_details (order_id, product_id, product_count) VALUES (1, 1, 1);
INSERT INTO ord_details (order_id, product_id, product_count) VALUES (1, 2, 1);
INSERT INTO ord_times (order_id, start_t, end_t) VALUES (1,'12/23/2013 12:24:38 PM', '12/23/2013  12:27:02 PM');

为什么“ ord_details.product_id = products._id”表达式在android中不起作用？

Answer 1

在连接OrderDetails和Products表时，尝试使用JOIN而不是LEFT JOIN，以便代码看起来像

SELECT orders.order_number, products.name as prname, products.price, 

ord_details.product_count, orders.order_sum, ord_times.start_t, ord_times.end_t FROM orders 

LEFT JOIN ord_details ON orders._id=ord_details.order_id 

JOIN products ON ord_details.product_id=products._id

LEFT JOIN ord_times ON orders._id=ord_times.order_id