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java - 消息 -"could not read a hi value - you need to populate the table: hibernate_sequence"

转载 作者:行者123 更新时间:2023-12-03 19:42:21 27 4
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我的问题如下:当我在“ postman ”应用程序中创建 POST 请求时。这就是我尝试发布的内容

  {"name": "John Doe", "email":"jdoe@test.com", "city": "London"}

我收到以下错误:
{
"timestamp": "2018-11-19T20:16:00.486+0000",
"status": 500,
"error": "Internal Server Error",
"message": "could not read a hi value - you need to populate the table: hibernate_sequence; nested exception is org.hibernate.id.IdentifierGenerationException: could not read a hi value - you need to populate the table: hibernate_sequence",
"path": "/api/ver01/product"
}

我在搜索框中寻找答案,但他们都没有帮助我。所以我认为问题出在sql代码中,但我不确定。整个项目是用 IntelliJ IDE 编写的。

这是我的产品课。
package com.hubertkulas.webstore.store.archetype;

import com.fasterxml.jackson.annotation.JsonFormat;
import com.fasterxml.jackson.annotation.JsonIgnoreProperties;

import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import java.math.BigDecimal;
import java.sql.Date;

@Entity
@JsonIgnoreProperties({"hibernateLazyInitializer", "handler"})
public class Product {

@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Long id;

private boolean contact;
private String email;
private String category;
private String name;
private String city;

private String model;
private BigDecimal price;

@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "MM-dd-yyyy")
private Date date;



public String getName() {
return name;
}

public void setName(String name) {
this.name = name;
}

public String getEmail() {
return email;
}

public void setEmail(String email) {
this.email = email;
}

public String getCity() {
return city;
}

public void setCity(String city) {
this.city = city;
}

public String getCategory() {
return category;
}

public void setCategory(String category) {
this.category = category;
}

public String getModel() {
return model;
}

public void setModel(String model) {
this.model = model;
}

public BigDecimal getPrice() {
return price;
}

public void setPrice(BigDecimal price) {
this.price = price;
}

public Date getDate() {
return date;
}

public void setDate(Date date) {
this.date = date;
}

public boolean isContact() {
return contact;
}

public void setContact(boolean contact) {
this.contact = contact;
}

public Long getId() {
return id;
}

// setter for id because Jackson will use it
public void setId(Long id) {
this.id = id;
}
}

这是我的 ProductController 类
package com.hubertkulas.webstore.store.controllers;
import com.hubertkulas.webstore.store.archetype.Product;
import com.hubertkulas.webstore.store.jparepository.ProductRepository;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.http.HttpStatus;
import org.springframework.web.bind.annotation.*;

import java.util.List;

@RestController
@RequestMapping("api/ver01/product")
public class ProductController {

//injecting ProductRepository when ProductController is called
@Autowired
private ProductRepository productRepository;

@GetMapping
public List<Product> list() {
//finds all of the records and returns it
return productRepository.findAll();
}

@PostMapping
@ResponseStatus(HttpStatus.OK)
public void create(@RequestBody Product product){
productRepository.save(product);
}



@GetMapping("/{id}")
public Product get(@PathVariable("id") long id){
// return specific record with added id
return productRepository.getOne(id);
}

}

这是我的 ProductRepository 接口(interface)
package com.hubertkulas.webstore.store.jparepository;

import com.hubertkulas.webstore.store.archetype.Product;
import org.springframework.data.jpa.repository.JpaRepository;

//Using Jpa for CRUD operations
public interface ProductRepository extends JpaRepository<Product, Long> {
}

这是我的数据库
CREATE TABLE
product
(
id BIGINT NOT NULL,
contact BOOLEAN NOT NULL,
email VARCHAR,
category VARCHAR,
name VARCHAR,
city VARCHAR,
date DATETIME,
price NUMERIC,
model VARCHAR,
PRIMARY KEY (id)
);

CREATE TABLE
hibernate_sequence
(
next_val BIGINT
);

INSERT INTO product (id, contact, email, category, name, city, date, price)
VALUES (1, 1, 'abraham@site.com', 'Electronics', 'Abraham Westbrom', 'New
York', 4419619200000, '3250');
INSERT INTO product (id, contact, email, category, name, city, date, price)
VALUES (2, 1, 'udon@site.com', 'Electronics', 'Udon Hon', 'London',
4419619200000, '799');
INSERT INTO product (id, contact, email, category, name, city, date, price)
VALUES (3, 0, 'mateuszsinus@site.com', 'Software', 'Mateusz Sinus',
'Warsaw', 4419619200000, '10000');

INSERT INTO hibernate_sequence (next_val) VALUES (4);

最佳答案

如果您使用 spring boot 为本地数据库创建模式并且 jpa 配置为执行自动创建删除,理想情况下您不会遇到这种情况。

spring.jpa.hibernate.ddl-auto=create-drop

但是在登台/生产中,您希望单独处理您的模式定义 (DDL),因此 hibernate_sequence 需要有一个初始值,并且 0 应该足以启动。它告诉程序库从哪个数字开始自动生成 id。
spring.jpa.hibernate.ddl-auto=validate

INSERT INTO <schema_name>.hibernate_sequence (next_val) VALUES (0);

以上适用于MYSQL

关于java - 消息 -"could not read a hi value - you need to populate the table: hibernate_sequence",我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/53382161/

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