PHP array_intersect_key 但保留 array2 中的值

Question

我有 2 个数组:

$array1 = ["b" => "no", "c" => "no", "d" => ["y" => "no"]];
$array2 = ["a" => "yes", "b" => "yes", "c" => "yes", "d" => ["x" => "yes", "y" => "yes", "z" => "yes"]];

我想返回 $array2 的成员，其键也存在于 $array1 中。

期望的输出:

$array3 = ["b" => "yes", "c" => "yes", "d" => ["y" => "yes"]];

基本上我需要与 array_intersect_key 相同的功能但我想保留 $array2 的值，而不是 $array1。

有这样的功能吗？还需要递归到子数组中。谢谢!

*编辑*正如 Andri 在 his comment 中所建议的那样，我试图翻转围绕 array_intersect_key($array2, $array1) 的参数，但在那种情况下我实际得到的是:

$array3 = ["b" => "yes", "c" => "yes", "d" => ["x" => "yes", "y" => "yes", "z" => "yes"]];

即 所有“d”的子级，只是因为在 $array1 中提到了“d”。

Answer 1

据我所知，没有内置函数，使用递归处理所有层的方法应该足够简单......

$array1 = ["b" => "no", "c" => "no", "d" => ["y" => "no"]];
$array2 = ["a" => "yes", "b" => "yes", "c" => "yes", "d" => ["x" => "yes", "y" => "yes", "z" => "yes"]];

function intersect_key_2 ( array $a1, array $a2 )   {
    foreach ( $a1 as $key1 => $value1)  {
        // If there is a matching element
        if ( isset($a2[$key1]) )    {
            // Update - if an array, use recursive call else just replace
            $a1[$key1] = ( is_array($value1) ) ? intersect_key_2 ( $value1, $a2[$key1])
                    : $a2[$key1];
        }
    }

    return $a1;
}

print_r(intersect_key_2($array1, $array2));

给予

Array
(
    [b] => yes
    [c] => yes
    [d] => Array
        (
            [y] => yes
        )

)