reactjs - 等待 useLazyQuery 响应

Question

我需要在按下提交按钮时调用查询，然后处理响应。

我需要这样的东西:

const [checkEmail] = useLazyQuery(CHECK_EMAIL)
const handleSubmit = async () => {
  const res = await checkEmail({ variables: { email: values.email }})
  console.log(res) // handle response
}

尝试 #1:

const [checkEmail, { data }] = useLazyQuery(CHECK_EMAIL)
const handleSubmit = async () => {
  const res = await checkEmail({ variables: { email: values.email }})
  console.log(data) // undefined the first time
}

提前致谢!

Answer 1

这对我有用:

const { refetch } = useQuery(CHECK_EMAIL, {
  skip: !values.email
})

const handleSubmit = async () => {
  const res = await refetch({ variables: { email: values.email }})
  console.log(res)
}