c# - c#中每个元素的两个数组比较的最小值

Question

我有下面哪个适用于第一个元素...我只是不知道如何为数组上的所有元素执行此操作...在此先感谢

        int[] ListNumb1 = new int[] { 2, 4, 6 };
        int[] ListNumb2 = new int[] { 3, 1, 9 };


        if (ListNumb1[0] < ListNumb2[0])
        {
            Console.WriteLine(ListNumb1[0]);
        }
        else
            Console.WriteLine(ListNumb2[0]);




        Console.ReadLine();

Answer 1

您可以使用 Enumerable.Zip将 2 个集合(数组)zip 在一起的方法，Math.Min以获得最低值。

var result = ListNumb1.Zip(ListNumb2, Math.Min)

完整示例

int[] ListNumb1 = new int[] { 2, 4, 6 };
int[] ListNumb2 = new int[] { 3, 1, 9 };

// Result will be an IEnumerbale<int>
var result = ListNumb1.Zip(ListNumb2, Math.Min)

Console.WriteLine(string.Join(",", result));

输出

2,1,6

_{注意 :要获取数组中的输出，只需调用 ListNumb1.Zip(ListNumb2, Math.Min).ToArray ()}

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或者您可以使用经典的for 循环

// Allocate the array
var results = new int[ListNumb1.Length];

// Iterate over each element in both arrays
for (var i = 0; i < ListNumb1.Length; i++)
   results[i] = Math.Min(ListNumb1[i], ListNumb2[i]);

_{注意 2 :这两个示例都假设数组长度相等，如果不是这样，您将需要验证和相应地采取行动}

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其他资源

• Enumerable.Zip Method

  Applies a specified function to the corresponding elements of two sequences, producing a sequence of the results.

• Math.Min Method

  Returns the smaller of two numbers.

• String.Join Method

  Concatenates the elements of a specified array or the members of a collection, using the specified separator between each element or member.