gpt4 book ai didi

javascript - 观察可构造样式表的变化

转载 作者:行者123 更新时间:2023-12-03 18:53:03 27 4
gpt4 key购买 nike

我有以下使用可构造样式表的代码片段。 (当点击按钮时,附加的可构造样式表会更新为随机颜色)。
我如何观察和聆听这种变化? (我想捕获元素上计算的样式更改,或者 - 更新的可构造样式表)

var div1 = document.getElementById("div1");


var observer = new MutationObserver(function (mutations) {
let text = "";
mutations.forEach(function (mutation) {
text += "changed " + mutation.attributeName;
});
document.getElementById("output").innerHTML += `<div>${text}</div>`;
});

var observerConfig = {
attributes: true
};

var targetNode = document.getElementById("div1");

document.getElementById("btnAttachStyleSheet").addEventListener("click", () => {
switch (Math.floor(Math.random() * 5)) {
case 1:
sheet.replaceSync(".color {color:blue}");
break;
case 2:
sheet.replaceSync(".color {color:yellow}");
break;
case 3:
sheet.replaceSync(".color {color:green}");
break;
case 4:
sheet.replaceSync(".color {color:brown}");
break;
default:
sheet.replaceSync(".color {color:pink}");
}
});
const sheet = new CSSStyleSheet();
document.adoptedStyleSheets = [sheet];
observer.observe(targetNode, observerConfig);
<h1>Adopted stylesheets</h1>
<button id="btnAttachStyleSheet">Update style sheet</button>
<div style="padding: 1rem;" id="div1" class="color">colored div</div>

<h3>mutations:</h3>
<div id="output"></div>

最佳答案

replaceSync 的规范没有提到触发任何事件。这不是 DOM 突变,所以你不能用 `MutationObserver.
相反,如果您控制调用 replaceSync 的代码, 调用你自己的函数 replaceSync然后引发特定于您的代码的事件(对于 replace 也是如此):

var div1 = document.getElementById("div1");

var targetNode = document.getElementById("div1");

document.getElementById("btnAttachStyleSheet").addEventListener("click", () => {
switch (Math.floor(Math.random() * 5)) {
case 1:
sheetReplaceSync(sheet, ".color {color:blue}");
break;
case 2:
sheetReplaceSync(sheet, ".color {color:yellow}");
break;
case 3:
sheetReplaceSync(sheet, ".color {color:green}");
break;
case 4:
sheetReplaceSync(sheet, ".color {color:brown}");
break;
default:
sheetReplaceSync(sheet, ".color {color:pink}");
}
});
const sheet = new CSSStyleSheet();
function sheetReplaceSync(sheet, ...args) {
const result = sheet.replaceSync(...args);
console.log("Changed!");
return result;
}
function sheetReplace(sheet, ...args) {
return sheet.replace(...args).then(result => {
console.log("Changed!");
return result;
});
};
document.adoptedStyleSheets = [sheet];
<h1>Adopted stylesheets</h1>
<button id="btnAttachStyleSheet">Update style sheet</button>
<div style="padding: 1rem;" id="div1" class="color">colored div</div>
<h3>mutations:</h3>
<div id="output"></div>

如果您不控制调用 replaceSync 的代码,您可以替换工作表上的方法(和 replace )以利用它,但如果可能的话,我会避免这样做:

var div1 = document.getElementById("div1");

var targetNode = document.getElementById("div1");

document.getElementById("btnAttachStyleSheet").addEventListener("click", () => {
switch (Math.floor(Math.random() * 5)) {
case 1:
sheet.replaceSync(".color {color:blue}");
break;
case 2:
sheet.replaceSync(".color {color:yellow}");
break;
case 3:
sheet.replaceSync(".color {color:green}");
break;
case 4:
sheet.replaceSync(".color {color:brown}");
break;
default:
sheet.replaceSync(".color {color:pink}");
}
});
const sheet = new CSSStyleSheet();
const replaceSync = sheet.replaceSync;
const replace = sheet.replace;
sheet.replaceSync = function(...args) {
const result = replaceSync.call(this, ...args);
console.log("Changed!");
return result;
};
sheet.replace = function(...args) {
return replace.call(this, ...args).then(result => {
console.log("Changed!");
return result;
});
};
document.adoptedStyleSheets = [sheet];
<h1>Adopted stylesheets</h1>
<button id="btnAttachStyleSheet">Update style sheet</button>
<div style="padding: 1rem;" id="div1" class="color">colored div</div>
<h3>mutations:</h3>
<div id="output"></div>

关于javascript - 观察可构造样式表的变化,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/66542814/

27 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com