iphone - 如何对包含 NSDictionary 的 NSArray 进行排序？

Question

我有一个像这样的plist:

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE plist PUBLIC "-//Apple//DTD PLIST 1.0//EN" "http://www.apple.com/DTDs/PropertyList-1.0.dtd">
<plist version="1.0">
<dict>
 <key>highscores</key>
 <array>
  <dict>
   <key>highscoreInSeconds</key>
   <string>9</string>
   <key>levelName</key>
   <string>1</string>
   <key>name</key>
   <string>Black</string>
  </dict>
  <dict>
   <key>highscoreInSeconds</key>
   <string>12</string>
   <key>levelName</key>
   <string>1</string>
   <key>name</key>
   <string>Black</string>
  </dict>
 </array>
</dict>
</plist>

现在我想按 highscoreInSeconds 对其进行排序。

   NSArray *paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES);
 NSString *plistDirectory = [paths objectAtIndex:0];
 NSString* fullPath = [plistDirectory stringByAppendingPathComponent:@"data.plist"];

 NSMutableDictionary* pData = [[NSMutableDictionary alloc] initWithContentsOfFile:fullPath];
 NSMutableArray* highscores = [pData valueForKey:@"highscores"];

现在我该如何排序？

非常感谢!:)

祝你有美好的一天。

PS:最后应该是这样的:

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE plist PUBLIC "-//Apple//DTD PLIST 1.0//EN" "http://www.apple.com/DTDs/PropertyList-1.0.dtd">
<plist version="1.0">
<dict>
 <key>highscores</key>
 <array>
  <dict>
   <key>highscoreInSeconds</key>
   <string>12</string>
   <key>levelName</key>
   <string>1</string>
   <key>name</key>
   <string>Black</string>
  </dict>
  <dict>
   <key>highscoreInSeconds</key>
   <string>9</string>
   <key>levelName</key>
   <string>1</string>
   <key>name</key>
   <string>Black</string>
  </dict>
 </array>
</dict>
</plist>

你不需要告诉我如何编写我知道的 plist。

Answer 1

我用这个:

NSArray* sorted = [highscoreAll sortedArrayUsingComparator:(NSComparator)^(NSDictionary *item1, NSDictionary *item2) {
            NSString *score1 = [item1 objectForKey:@"highscoreInSeconds"];
            NSString *score2 = [item2 objectForKey:@"highscoreInSeconds"];
            return [score1 compare:score2 options:NSNumericSearch];
            }];

并且成功了。