python - 不和谐.py : How do I get the name of the user who triggers on_member_update?

Question

async def on_member_update(before, after):
    print(str(after.username))
    if str(after.username) == "example username" # I'm looking for something like this
        print(str(af`enter code here`ter.username))
    if str(before.status) == "online":
        if str(after.status) == "offline":
            print("offline")
    elif str(before.status) == "offline":
        if str(after.status) == "online":
            print("online")

那么我怎样才能让它显示哪个用户触发了这个事件呢？

Answer 1

before和 after是成员对象，因此您可以轻松地从那里获取成员名称。
你的代码应该是这样的:

async def on_member_update(before, after):

    member = bot.get_guild(before.guild.id).get_member(before.id)
    print(member.name)

    if str(member.name) == "example username" 
        print(member.name)

    if str(before.status) == "online":
        if str(after.status) == "offline":
            print("offline")

    elif str(before.status) == "offline":
        if str(after.status) == "online":
            print("online")