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python - 错误 403 : HTTP status code is not handled or not allowed in scrapy

转载 作者:行者123 更新时间:2023-12-03 18:35:34 36 4
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这是代码,我写来抓取 justdial 网站。

import scrapy
from scrapy.http.request import Request

class JustdialSpider(scrapy.Spider):
name = 'justdial'
# handle_httpstatus_list = [400]
# headers={'User-Agent': "Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.1 (KHTML, like Gecko) Chrome/22.0.1207.1 Safari/537.1"}
# handle_httpstatus_list = [403, 404]
allowed_domains = ['justdial.com']
start_urls = ['https://www.justdial.com/Delhi-NCR/Chemists/page-1']
# def start_requests(self):
# # hdef start_requests(self):
# headers= {'User-Agent': 'Mozilla/5.0 (X11; Linux x86_64; rv:48.0) Gecko/20100101 Firefox/48.0'}
# for url in self.start_urls:
# self.log("I just visited :---------------------------------- "+url)
# yield Request(url, headers=headers)
def parse(self,response):
self.log("I just visited the site:---------------------------------------------- "+response.url)
urls = response.xpath('//a/@href').extract()
self.log("Urls-------: "+str(urls))

这是终端中显示的错误:
2017-08-18 18:32:25 [scrapy.core.engine] INFO: Spider opened
2017-08-18 18:32:25 [scrapy.extensions.logstats] INFO: Crawled 0 pages (at 0 pag
es/min), scraped 0 items (at 0 items/min)
2017-08-18 18:32:25 [scrapy.extensions.httpcache] DEBUG: Using filesystem cache
storage in D:\scrapy\justdial\.scrapy\httpcache
2017-08-18 18:32:25 [scrapy.extensions.telnet] DEBUG: Telnet console listening o
n 127.0.0.1:6023
2017-08-18 18:32:25 [scrapy.core.engine] DEBUG: Crawled (403) <GET https://www.j
ustdial.com/robots.txt> (referer: None) ['cached']
2017-08-18 18:32:25 [scrapy.core.engine] DEBUG: Crawled (403) <GET https://www.j
ustdial.com/Delhi-NCR/Chemists/page-1> (referer: None) ['cached']
2017-08-18 18:32:25 [scrapy.spidermiddlewares.httperror] INFO: Ignoring response
<403 https://www.justdial.com/Delhi-NCR/Chemists/page-1>: HTTP status code is n
ot handled or not allowed

我在 stackoverflow 上看到了类似的问题,我尝试了所有类似的方法,
你可以在代码中看到我尝试过的评论,
  • 更改了用户代理
  • 设置 handle_httpstatus_list = [400]

  • 注意:这个( https://www.justdial.com/Delhi-NCR/Chemists/page-1 )网站甚至没有在我的系统中被阻止。当我在 chrome/mozilla 中打开网站时,它正在打开。 ( https://www.practo.com/bangalore#doctor-search ) 站点也是同样的错误。

    最佳答案

    当您使用 user_agent 设置用户代理时蜘蛛属性,它开始工作。可能设置请求 header 是不够的,因为它会被默认用户代理字符串覆盖。所以设置蜘蛛属性

    user_agent = "Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.1 (KHTML, like Gecko) Chrome/22.0.1207.1 Safari/537.1"

    (与您设置 start_urls 的方式相同)并尝试一下。

    关于python - 错误 403 : HTTP status code is not handled or not allowed in scrapy,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45758194/

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