ios - 图片未存储在sqlite中

Question

我做了一个演示，将图像存储到数据库。目前我没有任何错误，但是我的图像没有存储在sqlite数据库中。
请查看以下代码，并告诉我我的错误在哪里。

DBManager类

sqlite3 *sqlite3DatabaseObject;
sqlite3_stmt* sqlite3Statement;
-(void)database
{

    directoryPaths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES);
    documentsDirectory = [directoryPaths objectAtIndex:0];
    NSString * databasePath = [[NSString alloc]initWithString:[documentsDirectory stringByAppendingPathComponent:@"informationdb.sql"]];
    NSFileManager *fileManager = [NSFileManager defaultManager];
    if ([fileManager fileExistsAtPath:databasePath] == NO) {
        const char *dbPath = [databasePath UTF8String];
        if (sqlite3_open(dbPath, &sqlite3DatabaseObject)== SQLITE_OK) {
            char * errorMessage;
            const char *sqlite3Query = "CREATE TABLE IF NOT EXISTS PICTURES (PHOTO BLOB)";
            if (sqlite3_exec(sqlite3DatabaseObject, sqlite3Query, NULL, NULL, &errorMessage)!= SQLITE_OK) {
                NSLog(@"failed = %@",sqlite3DatabaseObject);
            }
            sqlite3_close(sqlite3DatabaseObject);
        }else{
            NSLog(@"failed to create database");
        }
    }
}
- (void) SaveImagesToSql: (NSData*) imgData  {

    NSString *databasePath = [[NSBundle mainBundle] pathForResource:@"informationdb" ofType:@"sql"];

    const char* sqlite3Query = "INSERT INTO PICTURES (PHOTO) VALUES (?)";
    int openDatabaseResult = sqlite3_open_v2([databasePath UTF8String], &sqlite3DatabaseObject, SQLITE_OPEN_READWRITE , NULL);
    if (openDatabaseResult == SQLITE_OK) {
        int sqlite3Prepare = sqlite3_prepare_v2(sqlite3DatabaseObject, sqlite3Query, -1, &sqlite3Statement, NULL);
        if( sqlite3Prepare == SQLITE_OK ) {
            sqlite3_bind_blob(sqlite3Statement, 1, [imgData bytes], [imgData length], SQLITE_TRANSIENT);
            sqlite3_step(sqlite3Statement);
        }
        else
        {
            NSLog(@"Error is: %s", sqlite3_errmsg(sqlite3DatabaseObject));
        }
        sqlite3_finalize(sqlite3Statement);

    }
    else NSLog( @"Error is:  %s", sqlite3_errmsg(sqlite3DatabaseObject) );
    sqlite3_close(sqlite3DatabaseObject);
}

ViewController类

- (void)viewDidLoad {
    [super viewDidLoad];
    DBManager * dbmClass = [[DBManager alloc]init];
    [dbmClass database];

    imgView.userInteractionEnabled = YES;
    UITapGestureRecognizer *singleTap = [[UITapGestureRecognizer alloc]initWithTarget:self action:@selector(uploadOrCapture)];
    [singleTap setNumberOfTapsRequired:1];
    [imgView addGestureRecognizer:singleTap];

}
- (IBAction)btnSave:(id)sender {
    DBManager*dbmClass = [[DBManager alloc]init];
    NSData *imageInData = UIImagePNGRepresentation(imgView.image);
    [dbmClass SaveImagesToSql:imageInData];
    [self dismissViewControllerAnimated:YES completion:nil];
}

我无法找出问题所在。它成功执行了所有代码，但是当我从设备下载数据库并进行检查时，没有存储图像数据。

提前致谢。
米希尔

Answer 1

只需将此函数替换为我的代码即可，因为数据库路径错误

- (void) SaveImagesToSql: (NSData*) imgData  {

    directoryPaths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES);
    documentsDirectory = [directoryPaths objectAtIndex:0];
    NSString * databasePath = [[NSString alloc]initWithString:[documentsDirectory stringByAppendingPathComponent:@"informationdb.sql"]];

    const char* sqlite3Query = "INSERT INTO PICTURES (PHOTO) VALUES (?)";
    int openDatabaseResult = sqlite3_open_v2([databasePath UTF8String], &sqlite3DatabaseObject, SQLITE_OPEN_READWRITE , NULL);
    if (openDatabaseResult == SQLITE_OK) {
        int sqlite3Prepare = sqlite3_prepare_v2(sqlite3DatabaseObject, sqlite3Query, -1, &sqlite3Statement, NULL);
        if( sqlite3Prepare == SQLITE_OK ) {
            sqlite3_bind_blob(sqlite3Statement, 1, [imgData bytes], [imgData length], SQLITE_TRANSIENT);
            sqlite3_step(sqlite3Statement);
        }
        else
        {
            NSLog(@"Error is: %s", sqlite3_errmsg(sqlite3DatabaseObject));
        }
        sqlite3_finalize(sqlite3Statement);

    }
    else NSLog( @"Error is:  %s", sqlite3_errmsg(sqlite3DatabaseObject) );
    sqlite3_close(sqlite3DatabaseObject);
}

这是数据库截图



不要拖到您项目中的数据库。