c++ - 我的 if 语句打印在我的 while 循环中的每个 if 语句上，不管它是否为 false

Question

所以我正在制作一款文字冒险游戏，我只是提供编程指导。我有一个南北等脚本。然后是一个 if 语句，如果用户输入的不是方向，它会说这不是方向并循环到顶部，但它不起作用。即使我输入正确的输入，它也会始终打印 That is not a direction。谁能帮忙？

#include <iomanip>
#include <string>
#include <iostream>
using namespace std;



int main()
{
    string input;
    while (input != "north", "n", "south", "s", "east", "e") {
        cout << "Enter a direction" << endl;
        getline(cin, input);
        if (input == "north" || input == "n") {
            cout << "north" << endl;
        }
        if (input == "west" || input == "w") {
            cout << "west" << endl;
        }
        if (input == "east" || input == "e") {
            cout << "east" << endl;
        }
        if (input == "south" || input == "s") {
            cout << "south" << endl;
        }
        if (input != "n", "s", "e", "w")
        {
            cout << "That is not a direction" << endl;
        }
    }
    return 0;
}

Answer 1

正如我在评论中所说:

在 C++ 中，"north"、"n"、"south"、"s"、"east"、"e" 将始终计算为 "e" 和 "n"、"s"、"e"、"w" 将始终评估为 "w"

(对于所有可能的情况)进行这种比较的正确方法是:

 while (input != "north" && input != "n" && input != "south" && input != "s" && input != "east" && input != "e" && input != "west" && input != "w") {...}

如果是:

if (input != "n" || input != "s" || input != "e" || input != "w") {...}

Demo