iphone - 如何从iPhone sqlite数据库获取int数据

Question

我从这样的iPhone sqlite获取数据。我在表中有6条记录。

我的表中包含字段response_Id，participant_Id，answer_option，answer_text，update_date_time，但所有字段均为varchar字段，responsing_Id和participant_Id除外）

    + (void) getInitialDataToDisplay:(NSString *)dbPath {

CereniaAppDelegate *appDelegate = (CereniaAppDelegate *)[[UIApplication sharedApplication] delegate];

if (sqlite3_open([dbPath UTF8String], &database) == SQLITE_OK) {

    const char *sql = "select * from survey_question_responses";
    sqlite3_stmt *selectstmt;
    if(sqlite3_prepare_v2(database, sql, -1, &selectstmt, NULL) == SQLITE_OK) {

        while(sqlite3_step(selectstmt) == SQLITE_ROW) {

            NSInteger primaryKey = sqlite3_column_int(selectstmt, 0);
            Coffee *coffeeObj = [[Coffee alloc] initWithPrimaryKey:primaryKey];
                            coffeeObj.participant_Id=(This is integerin table)
            coffeeObj.answer_option = [NSString stringWithUTF8String:(char *)sqlite3_column_text(selectstmt, 2)];
            coffeeObj.answer_option = [NSString stringWithUTF8String:(char *)sqlite3_column_text(selectstmt, 3)];
            coffeeObj.answer_option = [NSString stringWithUTF8String:(char *)sqlite3_column_text(selectstmt, 4)];
            coffeeObj.answer_option = [NSString stringWithUTF8String:(char *)sqlite3_column_text(selectstmt, 5)];

            NSString*test=coffeeObj.answer_option;



            [appDelegate.coffeeArray addObject:coffeeObj];

            int count=[appDelegate.coffeeArray count];

            NSLog(test);
            NSLog(@"count is %d",count);


            [coffeeObj release];
        }
    }
    }
else
    sqlite3_close(database); //Even though the open call failed, close the database connection to release all the memory.
  }

当我NSlog数据时，它什么也没有显示。

Answer 1

查看SQLite Documentation。查询的所有结果值均在此处定义。
您可以将sqlite3_column_int用于整数，类似于sqlite3_column_text用于文本