sqlite - SQLite计数摘要查询

Question

我正在尝试查询汇总一周中每个员工的工作。例如，John Doe一周总共完成了12张票，其中4张为Break / Fixes，4张为Enhancement，另外4张未归类。

这是我到目前为止的内容：

SELECT (users.first_name || ' ' || users.last_name) AS Name,
  COUNT(tickets.id) AS 'Number of Tickets Closed',
  COUNT(tickets.category = 'Maintenance') AS 'Maintenance Tickets',
  COUNT(tickets.category = 'After Hours') AS 'After Hours Tickets',
  COUNT(tickets.category = 'Break Fix') AS 'Break Fix Tickets',
  COUNT(tickets.category = 'Enhancement') AS 'Enhancement Tickets',
  COUNT(tickets.category = '') AS 'Non Categorized Tickets'
FROM tickets, users
ON tickets.assigned_to=users.id
WHERE (tickets.status = 'closed') AND
  (tickets.closed_at >= '2011-07-16 00:00:00') AND
  (tickets.closed_at <= '2011-07-22 23:59:59')
GROUP BY Name;

这是一个示例结果：

约翰·杜1/10 10 10 10 10 10

约翰·杜2 2 2 2 2 2 2

约翰·杜3 25 24 24 24 24 24

约翰·杜4 2 2 2 2 2 2

约翰·杜（John Doe）5 12 10 10 10 10 10

约翰·杜（John Doe）6 7 7 7 7 7 7

该查询不能按我预期的那样正常工作，因为所有列的总数相同（关闭的票证总数，以下列似乎仅包含分类的票证。）帮助吗？

编辑

只想发布功能代码：

SELECT (users.first_name || ' ' || users.last_name) AS Name,
  COUNT(tickets.id) AS 'Number of Tickets Closed',
  COUNT(case tickets.category when 'Maintenance' then 1 else null end) AS 'Maintenance Tickets',
  COUNT(case tickets.category when 'After Hours' then 1 else null end) AS 'After Hours Tickets',
  COUNT(case tickets.category when 'Break Fix' then 1 else null end) AS 'Break Fix Tickets',
  COUNT(case tickets.category when 'Enhancement' then 1 else null end) AS 'Enhancement Tickets',
  COUNT(case tickets.category when '' then 1 else null end) AS 'Non Categorized Tickets'
FROM tickets, users
ON tickets.assigned_to=users.id
WHERE (tickets.status = 'closed') AND
  (tickets.closed_at >= '2011-07-16') AND
  (tickets.closed_at <= '2011-07-22')
GROUP BY Name;

Answer 1

您可能想要使用COUNT这样

...
    COUNT(case tickets.category when 'Maintenance' then 1 else null end),
    COUNT(case tickets.category when 'After Hours' then 1 else null end),
...