: 6 digits or 0-6 signs (digits or stars) with at least one star 的正则表达式

Question

如何编写正则表达式来验证此模式？

123456 - correct
*1 - correct
1* - correct
124** - correct
*1*2 - correct
* - correct
123456* - incorrect (size 7)
12345 - incorrect (size 5 without stars)

试过:

^[0-9]{6}$|^(([0-9]){1,6}([*]){1,5}){1,6}+$

但它允许有超过 6 个数字，并且不允许在数字之前加星号。
“*”符号没有最小/最大计数(但所有符号的最大计数为 6)。

Answer 1

干得好:

^(?:\d{6}|(?=.*\*)[\d*]{1,6}|)$

这是它的作用:

^            <-- Start of the string (we don't want to capture more than that)
  (?:          <-- Start a non captured group (it will be used to do the "or" part)
    \d{6}          <-- 6 digits, nothing more
    |            <-- OR
    (?=.*\*)       <-- Look ahead for a '*' (you could replace the first * with {0,5})
    [\d*]          <-- digits or '*'
    {1,6}          <-- repeated one to six times (we know from the look ahead that there will be at least one '*'
    |            <-- OR (nothing)
  )            <-- End the non capturing group
$            <-- End of the string

我不太确定你是否想要空 shell (但你说的是 0 到 6)，如果你真的想要 1 到 6，只需删除最后一个 |