asp.net-mvc - MVC中响应重定向后如何保持Server.GetLastError

Question

在我的 Global.asax 中，我定义了 Application_error 方法:

protected void Application_Error(object sender, EventArgs e)
{
    // Code that runs when an unhandled error occurs

    // Get the exception object.
    var exc                         = Server.GetLastError();

    //logics

    Response.Redirect(String.Format("~/ControllerName/MethodName?errorType={0}", errorAsInteger));
}

并且 exc 变量确实保留了最后一个错误，但是在从响应方法(MethodName)中的响应重定向后， Server.GetLastError()一片空白。我如何保留它或将它传递给 Response.Redirect(String.Format("~/ControllerName/MethodName?errorType={0}"所以我可以在我的方法体中将异常作为一个对象？

Answer 1

我想建议您不是 出现错误时重定向，以便保留 URL 并设置正确的 HTTP 状态代码。

相反，在 Application_Error 中执行您的 Controller

protected void Application_Error(object sender, EventArgs e)
{
    var exception = Server.GetLastError();

    var httpContext = ((HttpApplication)sender).Context;
    httpContext.Response.Clear();
    httpContext.ClearError();
    ExecuteErrorController(httpContext, exception);
}

private void ExecuteErrorController(HttpContext httpContext, Exception exception)
{
    var routeData = new RouteData();
    routeData.Values["controller"] = "Error";
    routeData.Values["action"] = "Index";
    routeData.Values["errorType"] = 10; //this is your error code. Can this be retrieved from your error controller instead?
    routeData.Values["exception"] = exception;

    using (Controller controller = new ErrorController())
    {
        ((IController)controller).Execute(new RequestContext(new HttpContextWrapper(httpContext), routeData));
    }
}

然后 ErrorController 是

public class ErrorController : Controller
{
    public ActionResult Index(Exception exception, int errorType)
    {
        Response.TrySkipIisCustomErrors = true;
        Response.StatusCode = GetStatusCode(exception);

        return View();
    }

    private int GetStatusCode(Exception exception)
    {
        var httpException = exception as HttpException;
        return httpException != null ? httpException.GetHttpCode() : (int)HttpStatusCode.InternalServerError;
    }
}