gpt4 book ai didi

delphi - 如何使用Delphi读取文本文件中的最后一行

转载 作者:行者123 更新时间:2023-12-03 18:18:15 25 4
gpt4 key购买 nike

我需要读取一些非常大的文本文件中的最后一行(以从数据中获取时间戳)。 TStringlist 是一种简单的方法,但它会返回内存不足错误。我正在尝试使用 seek 和 blockread,但是缓冲区中的字符都是无意义的。这与unicode有关吗?

    Function TForm1.ReadLastLine2(FileName: String): String;
var
FileHandle: File;
s,line: string;
ok: 0..1;
Buf: array[1..8] of Char;
k: longword;
i,ReadCount: integer;
begin
AssignFile (FileHandle,FileName);
Reset (FileHandle); // or for binary files: Reset (FileHandle,1);
ok := 0;
k := FileSize (FileHandle);
Seek (FileHandle, k-1);
s := '';
while ok<>1 do begin
BlockRead (FileHandle, buf, SizeOf(Buf)-1, ReadCount); //BlockRead ( var FileHandle : File; var Buffer; RecordCount : Integer {; var RecordsRead : Integer} ) ;
if ord (buf[1]) <>13 then //Arg to integer
s := s + buf[1]
else
ok := ok + 1;
k := k-1;
seek (FileHandle,k);
end;
CloseFile (FileHandle);

// Reverse the order in the line read
setlength (line,length(s));
for i:=1 to length(s) do
line[length(s) - i+1 ] := s[i];
Result := Line;
end;

基于 www.delphipages.com/forum/showthread.php?t=102965

测试文件是我在 excel 中创建的一个简单的 CSV(这不是我最终需要阅读的 100MB)。

    a,b,c,d,e,f,g,h,i,j,blank
A,B,C,D,E,F,G,H,I,J,blank
1,2,3,4,5,6,7,8,9,0,blank
Mary,had,a,little,lamb,His,fleece,was,white,as,snow
And,everywhere,that,Mary,went,The,lamb,was,sure,to,go

最佳答案

您确实必须从尾部到头部以大块读取文件。由于它太大,不适合内存 - 然后从头到尾逐行读取它会非常慢。使用 ReadLn - 慢两倍。

您还必须准备好最后一行可能以 EOL 结束,也可能不结束。

就我个人而言,我还会考虑三种可能的 EOL 序列:

  • CR/LF aka #13#10=^M^J - DOS/Windows 风格
  • 没有 LF 的 CR - 只是 #13=^M - 经典 MacOS 文件
  • 没有 CR 的 LF - 只是 #10=^J - UNIX 风格,包括 MacOS 版本 10

如果您确定您的 CSV 文件只会由 native Windows 程序生成,那么可以安全地假设使用了完整的 CR/LF。但如果可以有其他 Java 程序、非 Windows 平台、移动程序——我就不太确定了。当然,没有 LF 的纯 CR 是所有情况中可能性最小的。

uses System.IOUtils, System.Math, System.Classes;

type FileChar = AnsiChar; FileString = AnsiString; // for non-Unicode files
// type FileChar = WideChar; FileString = UnicodeString;// for UTF16 and UCS-2 files
const FileCharSize = SizeOf(FileChar);
// somewhere later in the code add: Assert(FileCharSize = SizeOf(FileString[1]);

function ReadLastLine(const FileName: String): FileString; overload; forward;

const PageSize = 4*1024;
// the minimal read atom of most modern HDD and the memory allocation atom of Win32
// since the chances your file would have lines longer than 4Kb are very small - I would not increase it to several atoms.

function ReadLastLine(const Lines: TStringDynArray): FileString; overload;
var i: integer;
begin
Result := '';
i := High(Lines);
if i < Low(Lines) then exit; // empty array - empty file

Result := Lines[i];
if Result > '' then exit; // we got the line

Dec(i); // skip the empty ghost line, in case last line was CRLF-terminated
if i < Low(Lines) then exit; // that ghost was the only line in the empty file
Result := Lines[i];
end;

// scan for EOLs in not-yet-scanned part
function FindLastLine(buffer: TArray<FileChar>; const OldRead : Integer;
const LastChunk: Boolean; out Line: FileString): boolean;
var i, tailCRLF: integer; c: FileChar;
begin
Result := False;
if Length(Buffer) = 0 then exit;

i := High(Buffer);
tailCRLF := 0; // test for trailing CR/LF
if Buffer[i] = ^J then begin // LF - single, or after CR
Dec(i);
Inc(tailCRLF);
end;
if (i >= Low(Buffer)) and (Buffer[i] = ^M) then begin // CR, alone or before LF
Inc(tailCRLF);
end;

i := High(Buffer) - Max(OldRead, tailCRLF);
if i - Low(Buffer) < 0 then exit; // no new data to read - results would be like before

if OldRead > 0 then Inc(i); // the CR/LF pair could be sliced between new and previous buffer - so need to start a bit earlier

for i := i downto Low(Buffer) do begin
c := Buffer[i];
if (c=^J) or (c=^M) then begin // found EOL
SetString( Line, @Buffer[i+1], High(Buffer) - tailCRLF - i);
exit(True);
end;
end;

// we did not find non-terminating EOL in the buffer (except maybe trailing),
// now we should ask for more file content, if there is still left any
// or take the entire file (without trailing EOL if any)

if LastChunk then begin
SetString( Line, @Buffer[ Low(Buffer) ], Length(Buffer) - tailCRLF);
Result := true;
end;
end;


function ReadLastLine(const FileName: String): FileString; overload;
var Buffer, tmp: TArray<FileChar>;
// dynamic arrays - eases memory management and protect from stack corruption
FS: TFileStream; FSize, NewPos: Int64;
OldRead, NewLen : Integer; EndOfFile: boolean;
begin
Result := '';
FS := TFile.OpenRead(FileName);
try
FSize := FS.Size;
if FSize <= PageSize then begin // small file, we can be lazy!
FreeAndNil(FS); // free the handle and avoid double-free in finally
Result := ReadLastLine( TFile.ReadAllLines( FileName, TEncoding.ANSI ));
// or TEncoding.UTF16
// warning - TFIle is not share-aware, if the file is being written to by another app
exit;
end;

SetLength( Buffer, PageSize div FileCharSize);
OldRead := 0;
repeat
NewPos := FSize - Length(Buffer)*FileCharSize;
EndOfFile := NewPos <= 0;
if NewPos < 0 then NewPos := 0;
FS.Position := NewPos;

FS.ReadBuffer( Buffer[Low(Buffer)], (Length(Buffer) - OldRead)*FileCharSize);

if FindLastLine(Buffer, OldRead, EndOfFile, Result) then
exit; // done !

tmp := Buffer; Buffer := nil; // flip-flop: preparing to broaden our mouth

OldRead := Length(tmp); // need not to re-scan the tail again and again when expanding our scanning range
NewLen := Min( 2*Length(tmp), FSize div FileCharSize );

SetLength(Buffer, NewLen); // this may trigger EOutOfMemory...
Move( tmp[Low(tmp)], Buffer[High(Buffer)-OldRead+1], OldRead*FileCharSize);
tmp := nil; // free old buffer
until EndOfFile;
finally
FS.Free;
end;
end;

附言。请注意一个额外的特殊情况 - 如果您使用 Unicode 字符(两个字节的字符)并给出奇数长度的文件(3 个字节、5 个字节等)-您将永远无法扫描起始的单个字节(半宽字符).也许你应该在那里添加额外的保护,比如 Assert( 0 = FS.Size mod FileCharSize)

PPS。根据经验,您最好将这些函数保留在表单类之外,因为为什么要混合它们?一般来说,您应该将关注点分成小块。读取文件与用户交互无关 - 因此最好将其卸载到额外的 UNIT。然后,您将能够在主线程或多线程应用程序中以一种形式或 10 种形式使用该单元的函数。就像乐高积木零件一样 - 它们体积小且独立,为您提供了灵 active 。

PPPS。这里的另一种方法是使用内存映射文件。 Google for Delphi 的 MMF implementations 和关于 MMF 方法的好处和问题的文章。我个人认为重写上面的代码以使用 MMF 会大大简化它,删除几个“特例”和麻烦的内存复制触发器。 OTOH 它会要求你对指针算法非常严格。

关于delphi - 如何使用Delphi读取文本文件中的最后一行,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36596713/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com