gpt4 book ai didi

iphone - UITableView footerView 带按钮,按钮不起作用

转载 作者:行者123 更新时间:2023-12-03 18:17:48 25 4
gpt4 key购买 nike

我正在尝试为我的 UITableView footerView 创建一个自定义 View ,其中有一个按钮。我可以在那里看到它,但是当我触摸它时,什么也没有发生...你能看到这里出了什么问题吗:

- (void)viewDidLoad {
[super viewDidLoad];

if(self.tableView.tableFooterView == nil) {
//allocate the view if it doesn't exist yet
UIView *footerView = [[UIView alloc] init];

//create the button
UIButton *addNewBtn = [UIButton buttonWithType:UIButtonTypeCustom];
//the button should be as big as a table view cell
[addNewBtn setFrame:CGRectMake(0, 0, 320, [AddMerchantTVC cellHeight])];

//set title, font size and font color
[addNewBtn setTitle:@"Add New" forState:UIControlStateNormal];
[addNewBtn.titleLabel setFont:[UIFont boldSystemFontOfSize:20]];
[addNewBtn setTitleColor:[UIColor blackColor] forState:UIControlStateNormal];
[addNewBtn addTarget:self action:@selector(addNew:) forControlEvents:UIControlEventTouchUpInside];

UIImageView *cellGradient = [[UIImageView alloc] initWithImage:[UIImage imageNamed:@"cellGradient.png"]];
cellGradient.frame = CGRectMake(0, 54, 320, 16);
[footerView addSubview:cellGradient];

//add the button to the view
[footerView addSubview:addNewBtn];
footerView.userInteractionEnabled = YES;
self.tableView.tableFooterView = footerView;
self.tableView.tableFooterView.userInteractionEnabled = YES;

[footerView release];
[cellGradient release];
}

- (void)addNew:(id)sender {
// This is never called
NSLog(@"Touched.");
}

最佳答案

您没有设置 footerView 的框架。将 footerView 的框架设置为至少与按钮一样高,否则触摸不会传递到按钮。

关于iphone - UITableView footerView 带按钮,按钮不起作用,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/3989740/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com