iphone - 使用 url 设置 UIImageView 图像

Question

是否可以读取图像的 url 并将 UIImageView 设置到该 url 处的图像？

Answer 1

对于这样一个简单的任务，我强烈建议不要集成诸如 Three20 之类的项目，该库是一个怪物，并且启动和运行起来不是很简单。

我会推荐这种方法:

NSString *imageUrl = @"http://www.foo.com/myImage.jpg";
[NSURLConnection sendAsynchronousRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:imageUrl]] queue:[NSOperationQueue mainQueue] completionHandler:^(NSURLResponse *response, NSData *data, NSError *error) {
    myImageView.image = [UIImage imageWithData:data];
}];

编辑 Swift 3.0

let urlString = "http://www.foo.com/myImage.jpg"
guard let url = URL(string: urlString) else { return }
URLSession.shared.dataTask(with: url) { (data, response, error) in
    if error != nil {
        print("Failed fetching image:", error)
        return
    }

    guard let response = response as? HTTPURLResponse, response.statusCode == 200 else {
        print("Not a proper HTTPURLResponse or statusCode")
        return
    }

    DispatchQueue.main.async {
        self.myImageView.image = UIImage(data: data!)
    }
}.resume()

*编辑 Swift 2.0

let request = NSURLRequest(URL: NSURL(string: urlString)!)

NSURLSession.sharedSession().dataTaskWithRequest(request) { (data, response, error) -> Void in

    if error != nil {
        print("Failed to load image for url: \(urlString), error: \(error?.description)")
        return
    }

    guard let httpResponse = response as? NSHTTPURLResponse else {
        print("Not an NSHTTPURLResponse from loading url: \(urlString)")
        return
    }

    if httpResponse.statusCode != 200 {
        print("Bad response statusCode: \(httpResponse.statusCode) while loading url: \(urlString)")
        return
    }

    dispatch_async(dispatch_get_main_queue(), { () -> Void in
        self.myImageView.image = UIImage(data: data!)
    })

    }.resume()