scala - 排序时间戳的scala arrayBuffer

Question

我有这个功能:

def getTime() : ArrayBuffer[Timestamp] = {
    val offset = Timestamp.valueOf("2015-01-01 00:00:00").getTime()
    val end = Timestamp.valueOf("2015-01-02 00:00:00").getTime()
    val diff = end - offset + 1

    val mList = ArrayBuffer[Timestamp]()

    val numRecords = 3
    var i = 0
    while (i < numRecords) {
      val rand = new Timestamp(offset + (Math.random() * diff).toLong)

      mList += rand
      i += 1
    }

  //  mList.toList.sortWith(_ < _); 
   // scala.util.Sorting.quickSort(mList.toArray);
}

我试图对数组进行排序，但不能。我收到此错误:

No implicit Ordering defined for java.sql.Timestamp.

我知道我需要定义如何进行排序。有没有办法像在 Java 中一样轻松地对其进行排序: Collections.sort(list);
或者有更好的方法使用 Scala？

Answer 1

或者，在您的类(class)中的某个地方定义它，您就可以开始了:

implicit def ordered: Ordering[Timestamp] = new Ordering[Timestamp] {
    def compare(x: Timestamp, y: Timestamp): Int = x compareTo y
}
getTime().sorted // now this will work just fine