php - 如何查看从 Objective C cocoa 发送到 php 的 GET 请求的响应

Question

我是 Objective C 和 Cocoa 框架的新手。我已经编写了以下代码并从 cocoa 向 php 发送请求，但无法从 php/server 获得响应，请帮忙。

NSString *fname=@"nam1";
NSString *lname=@"nam2";
NSString *urlString = [[NSString alloc] initWithFormat:@"http://url/send.php? 
first_name=%@&last_name=%@",fname,lname];
NSLog(urlString); 
NSURL *url = [ NSURL URLWithString:urlString];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
NSAlert *dq= [[NSAlert alloc] init];
[dq setMessageText:urlString];
[dq runModal];
[request setHTTPMethod:@"GET"];
NSURLConnection* connection = [[NSURLConnection alloc] initWithRequest:request 
delegate:self];  
[connection start];
NSAlert *d= [[NSAlert alloc] init];
[d setMessageText:@"connection"];
[d runModal];

对于响应，以下代码不起作用，我没有收到响应。

     - (void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse
    *)response 
     {
    _responseData = [[NSMutableData alloc] init];
      }

    -(void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data {
    // Append the new data to the instance variable

    [_responseData appendData:data];
    NSLog(@"response string: %@", _responseData);
    }

并响应这个 NSLog(@"response string: %@", _responseData);响应字符串:efbbbf3c 3f786d6c 20766572 73696f6e 3d22312e 30222065 6e636f64 696e673d 22757466 2d382220 3f3e0a3c 41727261 794f6646 697 26554 65787441 70694d73 673e0a3c 2f417272 61794f66 46697265 54657874 4170694d 73673e 出现在控制台中。

Answer 1

如果您只想将 NSData 作为 NSString 检查，您可以将以下内容放入 connectionDidFinishLoading: 方法中:

- (void)connectionDidFinishLoading:(NSURLConnection *)connection
{
    NSString *string = [[NSString alloc] initWithData:_responseData encoding:NSUTF8StringEncoding];
    NSLog(@"_responseData string = %@", string);
}

话虽如此，响应似乎是 XML:

<?xml version="1.0" encoding="utf-8" ?>
<ArrayOfFireTextApiMsg>
</ArrayOfFireTextApiMsg>

这是你所期待的吗？如果是这样，您可以使用NSXMLParser来解析它。

例如，假设您有一个包含一些数据的 XML 响应:

<?xml version="1.0" encoding="utf-8" ?>
<ArrayOfFireTextApiMsg>
    <FireTextApiMsg>Message1</FireTextApiMsg>
    <FireTextApiMsg>Message2</FireTextApiMsg>
    <FireTextApiMsg>Message3</FireTextApiMsg>
</ArrayOfFireTextApiMsg>

在connectionDidFinishLoading中，您可以执行以下操作:

- (void)connectionDidFinishLoading:(NSURLConnection *)connection
{
    NSXMLParser *parser = [[NSXMLParser alloc] initWithData:_responseData];
    [parser setDelegate:self];
    if ([parser parse])
        NSLog(@"fireTextApiMsgs = %@", self.fireTextApiMsgs);
    else
        NSLog(@"parse failed");
}

显然，您需要声明您的类符合委托(delegate)协议(protocol)并定义一些属性来跟踪您解析的值:

@interface ViewController () <NSXMLParserDelegate>

@property (nonatomic, strong) NSMutableArray  *fireTextApiMsgs;
@property (nonatomic, strong) NSMutableString *currentValue;

@end

你会实现 NSXMLParserDelegate方法，例如:

#pragma mark - NSXMLParserDelegate

- (void)parser:(NSXMLParser *)parser didStartElement:(NSString *)elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qName attributes:(NSDictionary *)attributeDict
{
    if ([elementName isEqualToString:@"ArrayOfFireTextApiMsg"])
        self.fireTextApiMsgs = [NSMutableArray array];
    else if ([elementName isEqualToString:@"FireTextApiMsg"])
        self.currentValue = [NSMutableString string];
}

- (void)parser:(NSXMLParser *)parser foundCharacters:(NSString *)string
{
    [self.currentValue appendString:string];
}

- (void)parser:(NSXMLParser *)parser didEndElement:(NSString *)elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qName
{
    if ([elementName isEqualToString:@"FireTextApiMsg"]) {
        [self.fireTextApiMsgs addObject:self.currentValue];
        self.currentValue = nil;
    }
}

- (void)parser:(NSXMLParser *)parser parseErrorOccurred:(NSError *)parseError
{
    NSLog(@"%s: %@", __FUNCTION__, parseError);
}

这将生成如下输出:

2013-12-20 12:08:55.167 XMLTestApp[12531:70b] fireTextApiMsgs = (    Message1,    Message2,    Message3)

显然，您的最终 XML 无疑会有所不同(我只是编了一个示例)，因此您必须根据 XML 响应的外观以及您尝试从中解析的内容来调整代码，但是希望这能说明这个想法。