python - Pydantic:如果没有传递，如何将默认值传递给变量？

Question

如果在字段中传递 None ，我可以在 Pydantic 中设置默认值吗？
我有以下代码，但在我看来，这里的验证器仅适用于模型的初始化，而不适用于其他情况。
我的代码:

class User(BaseModel):
     name: Optional[str] = ''
     password: Optional[str] = ''
     email: EmailStr
    

    @validator('name')
    def set_name(cls, name):
        return name or 'foo'

遇到的问题:

user = User(name=None, password='some_password', email='user@example.com')
print("Name is ", user.name)
# > 'Name is foo'

user.name = None
print("Name is ", user.name)
# > 'Name is None'

所需输出:

user = User(name='some_name', password='some_password', email='user@example.com')
user.name = None
print("Name is ", user.name)
# > 'Name is foo'

关于如何获得所需输出的任何想法？我认为拥有 getter 和 setter 将有助于解决这个问题。但是，我无法让它们在 Pydantic 模型中工作:
尝试实现 getter 和 setter:

class User(BaseModel):
    name: Optional[str] = ''
    password: Optional[str] = ''
    email: EmailStr

    def get_password(self):
        return self.password

    def set_password(self, password):
        self.password = hash_password(password)

    password = property(get_password, set_password)

user = User(name='some_name', password='some_password', email='user@example.com')
# > RecursionError: maximum recursion depth exceeded

我还尝试了属性装饰器:

class User(BaseModel):
     name: Optional[str] = ''
     password: Optional[str] = ''
     email: EmailStr

    @property
    def password(self):
        return self._password

    @password.setter
    def password(self, password):
        pwd_context = CryptContext(schemes=["bcrypt"], deprecated="auto")
        self._password = pwd_context.hash(password)

user = User(name='some_name', email='user@example.com')
user.password = 'some_password'
# > ValueError: "User" object has no field "password"

我也尝试覆盖 初始化 :

class User(BaseModel):
name: Optional[str] = ""
password: Optional[str] = ""
email: EmailStr

def __init__(self, name, password, email):
    pwd_context = CryptContext(schemes=["bcrypt"], deprecated="auto")
    password = pwd_context.hash(password)
    super().__init__(name=name, password=password, email=email)


user = User(name="some_name", password="some_password", email='user@example.com')
print(user.password)
# > AYylwSnbQgCHrl4uue6kO7yiuT20lazSzK7x # Works as expected

user.password = "some_other_password"
print(user.password)
# > "some_other_password" # Does not work

user.password = None
print(user.password)
# > None # Does not work either

Answer 1

您需要启用 validate_assignment模型配置中的选项:

from typing import Optional

from pydantic import BaseModel, validator


class User(BaseModel):
    name: Optional[str] = ''
    password: Optional[str] = ''

    class Config:
        validate_assignment = True

    @validator('name')
    def set_name(cls, name):
        return name or 'foo'


user = User(name=None, password='some_password', )
print("Name is ", user.name)


user.name = None
print("Name is ", user.name)

Name is  foo
Name is  foo