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sql - 将 CTE 应用于递归查询

转载 作者:行者123 更新时间:2023-12-03 17:37:36 25 4
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我正在尝试应用 CTE 和递归查询。数据库为 MariaDB 10.2 或更高版本。

业务规则如下:

  • 账户可以是控股或投资组合。
  • 持有由一定数量的货币组成。
  • 控股可以是活跃的和不活跃的。
  • 一个投资组合包含零个或多个账户,这些账户可以属于多个投资组合。
  • 在确定投资组合的值(value)时,每个账户的总值(value)乘以一个“权重”因子。

  • 我的架构如下(注意 char 用于 id 类型仅用于说明目的,但我真的会使用 int ):

    enter image description here
    CREATE TABLE IF NOT EXISTS accounts (
    id CHAR(4) NOT NULL,
    name VARCHAR(45) NOT NULL,
    type ENUM('holding', 'portfolio') NULL,
    PRIMARY KEY (id))
    ENGINE = InnoDB;

    CREATE TABLE IF NOT EXISTS holdings (
    accounts_id CHAR(4) NOT NULL,
    value DECIMAL(6,2) NOT NULL,
    active TINYINT NOT NULL,
    PRIMARY KEY (accounts_id),
    CONSTRAINT fk_holdings_accounts
    FOREIGN KEY (accounts_id)
    REFERENCES accounts (id)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
    ENGINE = InnoDB;

    CREATE TABLE IF NOT EXISTS portfolios (
    accounts_id CHAR(4) NOT NULL,
    PRIMARY KEY (accounts_id),
    CONSTRAINT fk_portfolios_accounts1
    FOREIGN KEY (accounts_id)
    REFERENCES accounts (id)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
    ENGINE = InnoDB;

    CREATE TABLE IF NOT EXISTS portfolios_has_accounts (
    portfolios_id CHAR(4) NOT NULL,
    accounts_id CHAR(4) NOT NULL,
    weight DECIMAL(4,2) NOT NULL,
    PRIMARY KEY (portfolios_id, accounts_id),
    INDEX fk_portfolios_has_accounts_accounts1_idx (accounts_id ASC),
    INDEX fk_portfolios_has_accounts_portfolios1_idx (portfolios_id ASC),
    CONSTRAINT fk_portfolios_has_accounts_portfolios1
    FOREIGN KEY (portfolios_id)
    REFERENCES portfolios (accounts_id)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION,
    CONSTRAINT fk_portfolios_has_accounts_accounts1
    FOREIGN KEY (accounts_id)
    REFERENCES accounts (id)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
    ENGINE = InnoDB;

    样本数据如下:
    INSERT INTO accounts(id,name,type) VALUES ('p1','portfolio1','portfolio'),('p2','portfolio2','portfolio'),('p3','portfolio3','portfolio'),('h1','holding1','holding'),('h2','holding2','holding'),('h3','holding3','holding'),('h4','holding4','holding');
    INSERT INTO holdings(accounts_id,value,active) VALUES ('h1','50','1'),('h2','40','0'),('h3','70','1'),('h4','40','1');
    INSERT INTO portfolios(accounts_id) VALUES ('p1'),('p2'),('p3');
    INSERT INTO portfolios_has_accounts(portfolios_id,accounts_id,weight) VALUES ('p1','h1','1'),('p1','p2','0.5'),('p2','h2','2'),('p2','p3','1'),('p3','h3','2'),('p3','h4','0.5');

    帐户
    id  name        type
    p1 portfolio1 portfolio
    p2 portfolio2 portfolio
    p3 portfolio3 portfolio
    h1 holding1 holding
    h2 holding2 holding
    h3 holding3 holding
    h4 holding4 holding

    投资组合
    portfolios_id
    p1
    p2
    p3

    控股
    id value active
    h1 50 1
    h2 40 0
    h3 70 1
    h4 40 1

    投资组合_has_accounts
    portfolios_id   accounts_id weight
    p1 h1 1
    p1 p2 0.5
    p2 h2 2
    p2 p3 1
    p3 h3 2
    p3 h4 0.5

    我的目标是找到:
  • 查找所有仅包含活跃持股的账户。给定样本数据,它是 p3、h1、h3 和 h4。 p2 不包括在内,因为它包括未激活的 h2,而 p1 不包括在内,因为它包括 p2。
  • 投资组合 p1 的总值(value)。给定样本数据,它是 170: 1*50 + 0.5*( 2*40 + 1*( 2*70 + 0.5*40 ) )
  • 持有量乘以得出投资组合 p1 的总值(value)的常数。给定样本数据,它们如下(注意1*h1 + 1*h2 + 1*h3 + 0.25*h4 = 170)

  • .
    id  weight
    h1 1
    h2 1
    h3 1
    h4 .25

    我怎样才能做到这一点?

    最佳答案

    请评论这些是否应该以不同的方式进行,或者从性能的角度来看,它们是否有任何重大问题?

    目标#1

    MariaDB [recursion]> WITH RECURSIVE t AS (
    -> SELECT accounts_id FROM holdings WHERE active=0
    -> UNION ALL
    -> SELECT pha.portfolios_id
    -> FROM portfolios_has_accounts pha
    -> INNER JOIN t ON t.accounts_id=pha.accounts_id
    -> )
    -> SELECT a.* FROM accounts a
    -> LEFT OUTER JOIN t ON t.accounts_id=a.id
    -> WHERE t.accounts_id IS NULL;
    +----+------------+-----------+
    | id | name | type |
    +----+------------+-----------+
    | h1 | holding1 | holding |
    | h3 | holding3 | holding |
    | h4 | holding4 | holding |
    | p3 | portfolio3 | portfolio |
    +----+------------+-----------+
    4 rows in set (0.00 sec)

    目标#2
    MariaDB [recursion]> WITH RECURSIVE t AS (
    -> SELECT pha.*, h.value
    -> FROM portfolios_has_accounts pha
    -> LEFT OUTER JOIN holdings h ON h.accounts_id=pha.accounts_id
    -> WHERE pha.portfolios_id="p1"
    -> UNION ALL
    -> SELECT pha.portfolios_id, pha.accounts_id, pha.weight*t.weight, h.value
    -> FROM t
    -> INNER JOIN portfolios_has_accounts pha ON pha.portfolios_id=t.accounts_id
    -> LEFT OUTER JOIN holdings h ON h.accounts_id=pha.accounts_id
    -> )
    -> SELECT SUM(weight*value) FROM t WHERE value IS NOT NULL;
    +-------------------+
    | SUM(weight*value) |
    +-------------------+
    | 170.0000 |
    +-------------------+
    1 row in set (0.00 sec)

    目标#3
    MariaDB [recursion]> WITH RECURSIVE t AS (
    -> SELECT pha.*, h.value
    -> FROM portfolios_has_accounts pha
    -> LEFT OUTER JOIN holdings h ON h.accounts_id=pha.accounts_id
    -> WHERE pha.portfolios_id="p1"
    -> UNION ALL
    -> SELECT pha.portfolios_id, pha.accounts_id, pha.weight*t.weight, h.value
    -> FROM t
    -> INNER JOIN portfolios_has_accounts pha ON pha.portfolios_id=t.accounts_id
    -> LEFT OUTER JOIN holdings h ON h.accounts_id=pha.accounts_id
    -> )
    -> SELECT accounts_id, weight FROM t WHERE value IS NOT NULL;
    +-------------+--------+
    | accounts_id | weight |
    +-------------+--------+
    | h1 | 1.00 |
    | h2 | 1.00 |
    | h3 | 1.00 |
    | h4 | 0.25 |
    +-------------+--------+
    4 rows in set (0.01 sec)

    MariaDB [recursion]>

    关于sql - 将 CTE 应用于递归查询,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45245347/

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