regex - 在cocoa中解析URL

Question

URL是: http://oauth.vk.com/blank.html#access_token=244832666666668A3MNA06F553247789a80224789a24555555553232323232323292IND193CIEN = 742

如何在Cocoa中解析它并获取access_token和user_id？

Answer 1

NSURL有一个-fragment方法，它返回#后面的字符串。

这就是用途。它非常基本，不支持实体(如 &)，它只是按 & 分割字符串，然后按 = 分割字符串。

@interface NSURL (SYBasicKeyValueParsing)
- (NSDictionary *)sy_keysAndValuesOfString:(NSString *)string;
- (NSDictionary *)sy_keysAndValuesOfFragment;
- (NSDictionary *)sy_keysAndValuesOfQuery;
@end

@implementation NSURL (SYBasicKeyValueParsing)

- (NSDictionary *)sy_keysAndValuesOfString:(NSString *)string
{
    if (!string) return nil;

    NSMutableDictionary *result = [NSMutableDictionary dictionary];

    for (NSString *pair in [string componentsSeparatedByString:@"&"]) {
        NSArray *keyAndValue = [pair componentsSeparatedByString:@"="];
        if ([keyAndValue count] == 2) {
            [result setObject:[keyAndValue objectAtIndex:1] forKey:[keyAndValue objectAtIndex:0]];
        }
    }
    return [[result copy] autorelease];
}

- (NSDictionary *)sy_keysAndValuesOfFragment
{
    return [self sy_keysAndValuesOfString:[self fragment]];
}

- (NSDictionary *)sy_keysAndValuesOfQuery
{
    return [self sy_keysAndValuesOfString:[self query]];
}

@end

因此，您的 URL 的 sy_keysAndValuesOfFragment 将导致以下结果:

{
    "access_token" = 244832666b8168a3mna06f03f5324789a8022455245532b032375f193ceab923;
    "expires_in" = 86400;
    "user_id" = 191742;
}