objective-c - EXC_BAD_ACCESS 错误，Objective-C 问题

Question

嘿，我是 Objective-C 的新手，而且也是使用 Cocoa 编程的新手。无论如何，我的代码看起来像这样:

int main(int argc, char *argv[])
{
printf("how many address would you like to input?\n");
int numAddresses;
scanf("%i", &numAddresses);
char *inputString;

NSMutableArray * arrayOfBooks = [NSMutableArray array];
for (int i = 0; i < numAddresses; ++i) {
 book * f = [[book alloc] init];


 printf("Please input the name of contact %i\n", i+1);
 scanf("%s",inputString);
 [f setName: inputString];

 printf("Please input the address of contact %i\n", i+1);
 scanf("%s", inputString);
 [f setAddress: inputString];

 printf("Please input the birthday of contact %i\n", i+1);
 scanf("%s", inputString);
 [f setBirthday: inputString];

 printf("Please input the phone number of contact %i\n", i+1);
 scanf("%s", inputString);
 [f setPhoneNumber: inputString];

 [f print]; 

 [arrayOfBooks addObject:f];
 [f release];
 }

for(int i = 0; i < numAddresses; i++){
 [arrayOfBooks[i] print];

}

return 0;
 }

我基本上只是在制作一个地址簿。当我输入名字时，它会抛出“EXC_BAD_ACCESS”错误。为什么？

#import "book.h"


@implementation book

-(void) setName: (char*) nameInput{
name = nameInput;

 }

-(void) setAddress: (char*) addressInput{
address = addressInput;

}

-(void) setPhoneNumber: (char*) phoneNumberInput{
phoneNumber = phoneNumberInput;
}

-(void) setBirthday: (char*) birthdayInput{
birthday = birthdayInput;
}

-(void) print{
printf("Name: %s\n", name);
printf("Address: %s\n", address);
printf("Phone Number: %s\n", phoneNumber);
printf("Birthday: %s\n", birthday);
 }

@end

编辑:我不再收到错误..但现在我有一个新问题。它提示我输入名称，然后立即提示我输入地址，然后我才有机会做任何事情。为什么会发生这种情况？

Answer 1

“inputstring”只是一个 char * - 它未分配，并且没有与之关联的存储。

您必须向其传递一个指向足够大小的数组的指针，使用“a”修饰符并传递一个指向指向scanf的char的指针为您分配。

请参阅 scanf 的手册页 http://developer.apple.com/library/mac/#documentation/Darwin/Reference/ManPages/man3/scanf.3.html