curl - 使用cURL崩溃

Question

我正在使用libcurl尝试将GET请求发送到服务器并保存响应。当我不使用CURLOPT_WRITEFUNCTION和CURLOPT_WRITEFDATA时，它工作正常，响应进入标准流，按下按钮后程序关闭。

但是，当我添加自己的函数和变量来保存响应时，响应末尾还有其他垃圾字符，按下按钮后程序崩溃。

#include <iostream>
#include <tchar.h>
#include <stdio.h>
#include <conio.h>

#include "curl/curl.h"
#include "curl/easy.h"

#define FAIL 0
#define PASS 1

size_t curlWrite(void*, size_t, size_t, void*);

CURL        *curl;
const char  *baseURL = "XXXX";
const char  *authHeader = "Authorization: Token token=YYYY";

int _tmain(int argc, _TCHAR* argv[])
{
    bool cURLStatus = PASS;
    CURLcode res;

    struct curl_slist *headers = NULL;
    headers = curl_slist_append(headers, authHeader);
    char *response;

    curl = curl_easy_init();
    if(curl)
    {
        curl_easy_setopt(curl, CURLOPT_URL, baseURL);
        curl_easy_setopt(curl, CURLOPT_HTTPGET, 1);
        curl_easy_setopt(curl, CURLOPT_HTTPHEADER, headers);
        curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, curlWrite);
        curl_easy_setopt(curl, CURLOPT_WRITEDATA, response);
        res = curl_easy_perform(curl);
        if(CURLE_OK != res) cURLStatus = FAIL;
    }
    else cURLStatus = FAIL;

    if(cURLStatus) printf("Response: %s", response);
    else           printf("Error: %s", curl_easy_strerror(res));

    curl_easy_cleanup(curl);

    _getch();

    return 0;
}

static size_t curlWrite(void *src, size_t size, size_t nmemb, void *dst)
{
    printf("Source: %s", src);
    memcpy(dst, src, size * nmemb);
    return size * nmemb;
}

这是我使用上面的代码得到的响应，后跟一个APPCRASH:

Source: {"current_bac":0,"time_until_sober":0}

0

Response: {"current_bac":0,"time_until_sober":0}P

如果我注释掉以下行(和printf):

curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, curlWrite);
curl_easy_setopt(curl, CURLOPT_WRITEDATA, response);

我得到这个:

{"current_bac":0,"time_until_sober":0}

我究竟做错了什么？

Answer 1

老兄，看着周围的类似问题，我确定自己必须自己编译libcurl。

实际上，解决方案是使用:

char *response = (char *)malloc( sizeof(*response) * 100 );

代替:

char *response;