ios - 显示远程通知期间应用崩溃

Question

我正在尝试使用Toast显示横幅，如果应用程序在其前台时收到通知。

简单的情况很好，没有任何问题。

- (void)application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo {
    UIView *parentView = [UIApplication sharedApplication].keyWindow.rootViewController.view;
    [parentView makeToast:@"toast"];
}

但是，当我尝试显示自己的自定义 View 时，在 EXC_BAD_ACCESS方法上出现了严重的 showToast错误:

- (void)application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo {
    UIView *bannerView = [[UIView alloc] initWithFrame:CGRectMake(0, 0, self.topController.view.frame.size.width, 80)];
    UIView *parentView = [UIApplication sharedApplication].keyWindow.rootViewController.view;
    bannerView.backgroundColor = [UIColor redColor];
    [parentView showToast: bannerView duration:3.0 position:CSToastPositionTop completion:nil];
}

- (void)application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo方法是进行此类行为编程的危险场所吗？对parentView的强引用似乎也不起作用，如何确定哪个对象被过度释放？

Answer 1

您可以直接在appdelegate窗口(位于所有 View 的顶层)上显示Toast，而不是立即获得父 View 。

-(void)application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo
{


    if (application.applicationState == UIApplicationStateActive)
    {
       [self.window makeToast:@"This is a piece of toast."];
    }
}