sql - 如何跳过子查询的匹配结果？

Question

使用sqlite3，我有一个看起来像这样的表：

+---------+-----------------+----------+-----------+--------+
| ArtId   |    Location     | ArtistID |  Title    |  Size  |
+---------+-----------------+----------+-----------+--------+
|  3      |      China      |   400    |   birds   | small  |
|  4      |      Samoa      |   670    |   stars   | large  |
|  5      |      Chile      |   427    |   clouds  | medium |
|  6      |        US       |   427    |   clouds  | small  |
|  7      |      France     |   123    |   collage | small  |
|  8      |      Spain      |   123    |   collage | large  |
|  9      |     Belarus     |   123    |   collage | medium |
+---------+-----------------+----------+-----------+--------+

我有一个查询，生成所有结果，其中唯一的结果是标题和艺术家重复的结果：

SELECT * 
FROM LiveArt c1, (SELECT Title, ArtistID FROM LiveArt GROUP BY Title, ArtistID) c2 
WHERE c1.Title = c2.Title AND c1.ArtistID = c2.ArtistID

产生下表：

+---------+-----------------+----------+-----------+--------+
| ArtId   |    Location     | ArtistID |  Title    |  Size  |
+---------+-----------------+----------+-----------+--------+
|  5      |      Chile      |   427    |   clouds  | medium |
|  6      |        US       |   427    |   clouds  | small  |
|  7      |      France     |   123    |   collage | small  |
|  8      |      Spain      |   123    |   collage | large  |
|  9      |     Belarus     |   123    |   collage | medium |
+---------+-----------------+----------+-----------+--------+

我要退货的是这样的：

+---------+-----------------+----------+-----------+--------+
| ArtId   |    Location     | ArtistID |  Title    |  Size  |
+---------+-----------------+----------+-----------+--------+
|  6      |        US       |   427    |   clouds  | small  |
|  8      |      Spain      |   123    |   collage | large  |
|  9      |     Belarus     |   123    |   collage | medium |
+---------+-----------------+----------+-----------+--------+

如何调整查询以执行此操作（跳过第一个匹配的结果）？

Answer 1

select * from tabName A
where A.ArtId !=
(
    select min(ArtId)
    from tabName B
    group by Title
    having A.Title=B.Title
);

ArtId       Location    ArtistID    Title       Size
----------  ----------  ----------  ----------  ----------
6           US          427         clouds      small
8           Spain       123         collage     large
9           Belarus     123         collage     medium