objective-c - 每十秒检查一次后台状况并发送通知

Question

我正在开发一个适用于 Mac OS X 的应用程序。我的应用程序每十秒检查一次，如果条件成立，该应用程序会发送一条 Growl 通知。

我已经对 Growl 通知和检查进行了编码。我只需要知道如何使此检查每十秒重复一次，并且每次在后台发送通知(如果为真)。

请写出准确的代码，因为我对 Objective-C 很陌生。谢谢:D

----------------------------编辑-------------- ----------------------------------

目前我正在使用这个:

//  MyApp_AppDelegate.m

#import "MyApp_AppDelegate.h"

@implementation MyApp_AppDelegate

- (void)awakeFromNib {
    return;
}


-(void)applicationDidFinishLaunching:(NSNotification*)aNotification {

    // grwol:
    NSBundle *myBundle = [NSBundle bundleForClass:[MyApp_AppDelegate class]];
    NSString *growlPath = [[myBundle privateFrameworksPath] stringByAppendingPathComponent:@"Growl-WithInstaller.framework"];
    NSBundle *growlBundle = [NSBundle bundleWithPath:growlPath];

    #include <unistd.h>

    int x = 0;
    int l = 10; // time/repeats
    int t = 10; //seconds
    while ( x <= l ) {

        // more code here only to determine sendgrowl value...

        if(sendgrowl) {
            if (growlBundle && [growlBundle load]) {
                // more code to sends growl
            } else {
                NSLog(@"ERROR: Could not load Growl.framework");
            }
        }

        // do other stuff that doesn't matter...

        // wait:
        sleep(t);

        x++;
    }
}

/* Dealloc method */
- (void) dealloc { 
    [super dealloc]; 
}

@end

Answer 1

您正在寻找的确切代码可以在这里找到: Time Programming Topics