cocoa - 命名多个 NSButton

Question

我写了一些糟糕的代码，但它有效。有更好的方法来写这个吗？ _decade.x 是 NSButton。

int baseDecade = 1940;
NSString *title;
int currentDecade = 0;

- (IBAction)nameDecade:(id)sender {

    currentDecade = baseDecade;
    title = [NSString stringWithFormat: @"%ld", (long)currentDecade];
    _decade1.stringValue = title;

    currentDecade = currentDecade +10;
    title = [NSString stringWithFormat: @"%ld", (long)currentDecade];
    _decade2.stringValue = title;

    currentDecade = currentDecade +10;
    title = [NSString stringWithFormat: @"%ld", (long)currentDecade];
    _decade3.stringValue = title;

Answer 1

在 iOS 中，您可以将按钮放在一个 IBOutletCollection 中在界面生成器中，或者在 NSArray 中(如果您通过代码创建按钮)。有了该 socket 集合/数组，您可以使用循环通过集合中的索引来引用 _decadeN:

@property (nonatomic, retain) IBOutletCollection(UIButton) NSArray *decadeButtons;
...
for (int i = 0 ; i != decadeButtons.count ; i++) {
    UIButton * decade = decadeButtons[i];
    NSString *title = [NSString stringWithFormat: @"%ld", (long)(baseDecade+10*i)];
    decade.stringValue = title;
}

编辑: OSX does not support IBOutletCollections yet ，因此您需要将 _decadeN 按钮放入数组中:

// I am using the new array literal syntax; using arrayWithObjects will work too.
NSArray *decadeButtons = @[_decade1, _decade2, _decade3];
// Use the same loop as above:
for (int i = 0 ; i != decadeButtons.count ; i++) {
    UIButton * decade = decadeButtons[i];
    NSString *title = [NSString stringWithFormat: @"%ld", (long)(baseDecade+10*i)];
    decade.stringValue = title;
}